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ohaa [14]
3 years ago
5

A common cooking vinegar is 5.0% acetic acid (ch3cooh. how many molecules of acetic acid are present in 41.9 g vinegar?

Chemistry
1 answer:
UkoKoshka [18]3 years ago
6 0
To calculate the number of molecules ch3cooh in a given amount of vinegar, we first need to determine the amount of ch3cooh in the solution by multiplying the percent <span>ch3cooh with the sample amount. Then, convert g to moles and use avogadro's number. We do as follows:

41.9 g vinegar solution ( .05 g </span><span>ch3cooh / g vinegar solution ) (1 mol / 60.05 g ) ( 6.022x10^23 g / 1 mol ) = 2.1x10^22 molecules </span><span>ch3cooh</span>
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