Coco buys a very large rectangular chocolate bar and decides that each day, she

Mathematics

2 answers:

olasank [31]3 years ago

7 0

On each of the six days Coco ate a square piece of chocolate with side length 15 cm, 15 cm, 9 cm, 6 cm, 3 cm and 3 cm, respectively. Since we know the originally chocolate bar was a rectangle the 6 squares must fit together as shown. The length of the longer side of the original chocolate bar, then, was 15 + 15 + 9 =39 cm

N76 [4]3 years ago

3 0

Answer: 39

Step-by-step explanation:

On each of the six days Coco ate a square piece of chocolate with side length 15 cm, 15 cm, 9 cm, respectively. Then find the slope versus. 15*15+9*1=236. Then you have to do 236-200=36. Later 36+3, since there were three numbers to get 39.

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Help me on this question! Jake can carry 6 1/4 pounds of wood in from the barn.His father can carry 1 5/7 times as much as jake.

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$\text{ Jake father can carry } 10\frac{5}{7} \text{ or } \frac{75}{7} \text{ pounds }$

Solution:

From given question,

Number of pounds Jake carry = $6\frac{1}{4} \text{ pounds }$

Number of pounds his father carry is $1\frac{5}{7}$ times as much as jake

To find: Number of pounds Jake father can carry

Convert the mixed fractions to improper fractions

Multiply the whole number part by the fraction's denominator.

Add that to the numerator.

Then write the result on top of the denominator

$\rightarrow 6\frac{1}{4} = \frac{4 \times 6+1}{4} = \frac{25}{4}\\\\\rightarrow 1\frac{5}{7} = \frac{7 \times 1+5}{7} = \frac{12}{7}$

Then according to question,

$\text{Pounds father carry } = \frac{12}{7} \text{ times the pounds jake carry }\\\\\text{Pounds father carry } = \frac{12}{7} \times \frac{25}{4}\\\\\text{Pounds father carry } = \frac{75}{7}\\\\\text{In terms of mixed fractions, }\\\\\text{Pounds father carry } = \frac{75}{7} = 10\frac{5}{7}$