<span>A) 2x + 4y = 38
B) 10x + 3y = 105
Multiplying A) by -5
A) -10x -20y = -190 then adding it to B)
</span><span>B) 10x + 3y = 105
-17y = -85
y = 5
x = 9
</span>
(y + z2) * x
(5 + 3(2)) * 2
(5 + 6) * 2
11 * 2
Your answer is 22
(x-h)²+(y-k)²=r² is the equation of a circle with radius of r
so if x-h=4 and y-k=3 then
4²+3²=r²
16+9=r²
25=r²
sqrt both sides
5=r
radius is 5 units
Answer:
{8,-4,-10}
Step-by-step explanation:
re arrange relation, im going to assume x is the domain input and y is the range.
-3x+2=y
plug in every element of the set x to get the range set y
-3(-2)+2=y
y=8
-3(2)+2=y
y=-4
-3(4)+2=y
y=-10
so the range is {8,-4,-10}
