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3 years ago

Help me pleaseee!.!.!.

Mathematics

1 answer:

Crazy boy [7]3 years ago

4 0

May I suggest Socratic?

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I need help solving systems of linear equations by substitution. <br> {4x+3y=14<br> 3x-2y=2

Sauron [17]

Answer:

A) 4x+3y=14

B) 3x-2y=2

We multiply equation A) by (2/3)

A) (8/3) x +2y = 28/3 then we add this to equation B)

B) 3x-2y=2

5 (2/3) x = 11 (1/3)

x = 2

A) 4 * 2 + 3 y = 14

A) 3y = 6

y = 2

Step-by-step explanation:

4 0

3 years ago

The area of a square is 144 square centimeters.<br> What is the length of one side of the square?

babunello [35]

What is the length of one side of the square?

ANSWER ---Take the square root of 144.
so it is -------- 12

6 0

3 years ago

Read 2 more answers

Matrix A has dimensions 2x3. Matrix B has dimensions 3x6. These two matrices can be multiplied

alexdok [17]

If you mean A*B, then yes since,

number of columns in matrix A = number of rows in matrix B

ie the inner dimensions both match up (both are 3)

However, B*A is not defined

8 0

3 years ago

When expressing sets, you may write "inf" for infinity and "U" for union.

GarryVolchara [31]

Answer:

The complement of the given set in interval notation is $(-\infty,-5]\cup(6,\infty)$ . It can we written as (-inf,5]U(6,inf).

Step-by-step explanation:

The given set in interval notation is

(−5,6]

It means the set is defined as

$A=\{x|x\in R,-5$

If B is a set and U is a universal set, then complement of set B contains the elements of universal set but not the elements of set B.

Here, universal set is R, the set set of all real numbers.

$U=\{x|x\in R\}$

The complement of the given set is

$A^c=U-A$

$A^c=\{x|x\in R,-\infty$

Complement of the given set in interval notation is

$A^c=(-\infty,-5]\cup(6,\infty)$

Therefore the complement of the given set in interval notation is $(-\infty,-5]\cup(6,\infty)$ . It can we written as (-inf,5]U(6,inf).

3 0

3 years ago

There has been a trend toward less driving in the last few years, especially by young people. From 2001 to 2009 the annual vehic

rodikova [14]

Answer: 1537.

Step-by-step explanation:

Formula for sample size :-

$n=(\dfrac{z_{\alpha/2}\cdot \sigma}{E})^2$

Given : $\sigma=2000$

Margin of error : E= 100

Critical value of 95% confidence : $z_{\alpha/2}=1.96$

Now, the required sample size will be :-

$n=(\dfrac{1.96\cdot 2000}{100})^2\\\\=1536.64\approx1537$

Hence, the minimum sample size required = 1537.

3 0

4 years ago