The function of the length z in meters of the side parallel to the wall is A(z) = z/2(210 - z)
<h3>How to write a function of the length z in meters of the side parallel to the wall?</h3>
The given parameters are:
Perimeter = 210 meters
Let the length parallel to the wall be represented as z and the width be x
So, the perimeter of the fence is
P = 2x + z
This gives
210 = 2x + z
Make x the subject
x = 1/2(210 - z)
The area of the wall is calculated as
A = xz
So, we have
A = 1/2(210 - z) * z
This gives
A = z/2(210 - z)
Rewrite as
A(z) = z/2(210 - z)
Hence, the function of the length z in meters of the side parallel to the wall is A(z) = z/2(210 - z)
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<span>-3x + 2y = 2 eq (1)
7x - 3y = 7 eq (2)
Mutiply eq (1) by 3 and eq (2) by 2:
-9x + 6y = 6
14x - 6y = 14
Add th two new equations:
-9x + 14x = 6 + 14
=> 5x = 20
=> x = 20/5
=> x = 4
Now from eq (1)
-3(4) + 2y = 2
=> 2y = 2 + 12
=> 2y = 14
=> y = 14 / 2
=> y = 7
So the ordered pair is (4,7)
Answer: option B. (4,7)
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