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Mathematics

1 answer:

irinina [24]3 years ago

5 0

$A=h(a+b) \\ \\ A=ha+hb \\ \\ A-ha=hb \\ \\ \cfrac{A-ha}{h}=b$

Answer is A.

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Solve 6 + 5 √ 2 4 9 − 2 x = 7

NISA [10]

$6+5\sqrt{249}-2x=7 \\-2x=7-6-5\sqrt{249} \\-2x\approx-77.9 \\x\approx\frac{-77.9}{2}\approx38.95$

Hope this helps.

7 0

3 years ago

Find the arc length for a circle with diameter 10 inches and central angle 60 degrees. Round to the nearest tenth.

UkoKoshka [18]

Answer:

C. 5.2 cm

Step-by-step explanation:

Arc length formula:

$s = \dfrac{n}{360^\circ} 2 \pi r$

where s = arc length

n = central angle of arc

r = radius of circle

diamter = d = 10 cm

r = d/2 = 10 cm/2 = 5 cm

n = 60 deg

$s = \dfrac{n}{360^\circ} 2 \pi r$

$s = \dfrac{60^\circ}{360^\circ} 2 \times 3.14159 \times 5 ~cm$

$s = 5.2~cm$

Answer: 5.2 cm

6 0

3 years ago

If y varies inversely as x and y= 2/5 when x= 2, find y when x= 1

Alik [6]

Answer:

y = 4/5

Step-by-step explanation:

Since, y varies inversely as x.

$\therefore \: y = \frac{k}{x} \\ (k = constant \: of \: proportionality) \\ \therefore \: xy = k...(1) \\ plug \: y = \frac{2}{5} \: and \: x = 2 \: in \: (1) \\ 2\times \frac{2}{5} = k \\ \implies \: k = \frac{4}{5} \\ substituting \: k= \frac{4}{5} \: in \: (1) \\ xy = \frac{4}{5} ..(2) \\ this \: i s \: the \: equation \: of \: variation \\ plug \: x = 1 \: in \: (2) \\ 1 \times y = \frac{4}{5} \\ \huge \red{ \boxed{y = \frac{4}{5} }}$