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Tasya [4]
3 years ago
5

A 42.0g sample of compound containing only C and H was analyzed. The results showed that the sample contained 36.0g of C and 6.0

g of H.
Which of the following questions about the compound can be answered using the results of the analysis?

A) What was the volume of the sample?
B) What is the molar mass of the compound?
C) What is the chemical stability of the compound?
D) What is the empirical formula of the compound?
Chemistry
1 answer:
user100 [1]3 years ago
5 0

Answer:

What is the empirical formula of the compound?

Explanation:

When the relative masses of elements in a hydrocarbon are given, it is possible to use this information to obtain the empirical formula by dividing the given masses of each element by the relative atomic masses of the element. The lowest ratio is now used to divide through to obtain the empirical formula of the compound.

The empirical formula only shows that ratio of atoms of each element present in the compound. From the information provided, the empirical formula of the compound is CH2. Hence the answer.

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In an experiment to determine how to make sulfur trioxide, a chemist combines 32.0 g of sulfur with 50.0 g of oxygen. She finds
LuckyWell [14K]

Answer:

The chemist needs to react 40 g of sulfur with 60 g of oxygen to make 100 g of sulfur trioxide.

Explanation:

2S (s) + 3O₂ (g) → 2SO₃ (g)

64g    + 96g     →  160 g

32g    + 48g     →   80 g

   x     +     y      →  100 g

   

1 mol SO₃ ___ 80g

     n _______ 100g

         n = 1.25 mol SO₃

1 mol S ___ 32 g

1,25 mol S __ 40 g

1 mol O₂ ___ 32 g

1,875 mol O₂ ___ 60 g

4 0
3 years ago
5400 L to KL<br> With work??
Gnesinka [82]

Answer:

5.4KL

Explanation:

Divide by 1000

3 0
3 years ago
The element bromine is a reddish-brown liquid at room temperature, with a density of 3.103g/mL. What is the mass, in grams, of 1
Anastaziya [24]
The element bromine is not a reddish-brown liquid. Liquid is the substance bromine.

M=DV

M=3.103 g/mL * 19.8 mL = 61.44 g
6 0
3 years ago
Which of the following is not a valid set of quantum numbers
ASHA 777 [7]
I believe the answer is C, n = 3, l = 3, m = 3. The magnetic quantum number, or 

<span>ml</span>, can only take values that range from <span>−l</span> to <span>+l</span>, as you can see in the table above.

For option C), the angular momentum quantum number of equal to ++2<span>, which means that <span>ml</span> can have a maximum value of </span>+2<span>. Since it is given as having a value of </span>+3**, this set of quantum numbers is not a valid one.

The other three sets are valid and can correctly describe an electron.

3 0
3 years ago
Read 2 more answers
19. What is sthe mass of 6.02 x 1024 atoms
alekssr [168]

The mass of magnesium in 6.02 \times 10^{24} atoms is 240 g.

Answer: Option A

<u>Explanation:</u>

First, we have to convert the atoms to moles of magnesium.

We know that 6.02 \times 10^{24} atoms are present in 1 mole of magnesium. So,

    \text { 1 atom }=\frac{1}{6.02 \times 10^{24}} \text { moles }

    6.02 \times 10^{24} \text { atoms }=\frac{6.02 \times 10^{24}}{6.02 \times 10^{23}} \text { moles }=10 \text { moles }

Thus,

     Mass of M g= molar mass of M g \times No. of moles of M g

     \text { Mass of } M g=24 \times 10=240 g

Thus, 240 g of Magnesium is present in 6.02 \times 10^{24} atoms.

4 0
3 years ago
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