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3 years ago

5

What is the general trend for electron affinity values going across a period? The

2 answers:

KIM [24]3 years ago

8 0

Answer:

a.the values become more negative

Explanation:

k0ka [10]3 years ago

5 0

Answer: The values become more negative

Explanation: I just took the quiz and got it correct :)

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An aqueous solution of blue copper(II) ions can react with chloride ions to form a yellow copper compound. The ionic equation fo

klio [65]

Since the forward reaction is endothermic (heat is consumed in the reaction) that means that the enthalpy change for the forward reaction is a positive value.
Therefore, i would say that the reverse or backward reaction is exothermic (heat is released in the reaction to the sorroundings) and that the enthalpy change is a negative value.

5 0

3 years ago

3. Determine the Zeff value of Uranium, also indicate (based on your answer with mathematical calculations) which electron will

Ilya [14]

Explanation:

Electronic configuration of uranium is given below -

1s²2s²2p⁶3s²3p⁶3d¹⁰4s²4p⁶4d¹⁰5s²5p⁶4f¹⁴5d¹⁰6s²6p⁶5f³6d¹7s2²

Effective nuclear charge (Z eff) = Atomic number (Z) - Shielding constant (S)

<u> Value of Shielding constant (S) can be calculated by using slater's rule : </u>

S = 1 (0.35) + 9 (0.85) + 81 (1.00)

S = 0.35 + 7.65 + 81.00

S = 89

So,

Zeff = Z - S

Zeff = 92 - 89

<u> Zeff = 3 </u>

Hence, Effective nuclear charge (Zeff) of uranium = <u>3 </u>

5s electron is closest to the nucleus.

3 0

3 years ago

How many moles are in 89 liters of water vapor?

Brut [27]

Answer:

4 moles

Explanation:

A mole is equal to 6.02214076 × 1023 of any chemical unit (atoms, molecules, ions)

To find number of moles in 89 litres of water vapor use the following formula:

1 mole = 22.4 L

That is 1 L = $\frac{1}{24}$ mole

Volume of water vapor = 89 litres

Therefore,

Number of moles in 89 litres = $\frac{89}{24}=3.7$ ≈ 4 moles

5 0

3 years ago

The [OH-] of an aqueous solution is 3.5 x 10-5. What is the [H+]?

Sergeeva-Olga [200]

Answer: The concentration of hydrogen ion in the given solution is $2.81 \times 10^{-10}$ .

Explanation:

pOH of a solution is the negative logarithm of concentration of hydroxide ions.

Hence, if $[OH^{-}]$ is $3.5 \times 10^{-5}$ then its pOH value is calculated as follows.

$pOH = -log [OH^{-}]\\= -log (3.5 \times 10^{-5})\\= 4.45$

Now, the relation between pH and pOH is as follows.

pH + pOH = 14

pH + 4.45 = 14

pH = 14 - 4.45

= 9.55

And, pH is the negative logarithm of concentration of hydrogen ions. Hence, $[H^{+}]$ is calculated as follows.

$pH = -log [H^{+}]\\9.55 = -log [H^{+}]\\H^{+} = 2.81 \times 10^{-10}$

Thus, we can conclude that the concentration of hydrogen ion in the given solution is $2.81 \times 10^{-10}$ .

4 0

3 years ago

How does an atom become a positively charged ion? by gaining one or more electrons by gaining one or more neutrons by losing one

erma4kov [3.2K]

By losing one or more electrons

4 0

3 years ago