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DENIUS [597]
2 years ago
5

What is the general trend for electron affinity values going across a period? The

Chemistry
2 answers:
KIM [24]2 years ago
8 0

Answer:

a.the values become more negative

Explanation:

k0ka [10]2 years ago
5 0

Answer: The values become more negative

Explanation: I just took the quiz and got it correct :)

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Elenna [48]

Answer:

Precipitate

Explanation:

A precipitate is a solid formed from a chemical solution

7 0
1 year ago
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Why does surface area of a reactant influence the rate of the reaction?
telo118 [61]

because it can influence how frequently and sufficiently the particles collide depending on the space it has to do so, for example a large surface area would be have a slower rate of reaction and a lower temperature. (the rate of reaction in terms of concentration, it is diffused from high to low) 
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It is safe to stand on the top step of a ladder provided it is braced properly. A) True B) False
Roman55 [17]

FALSE You are never allowed to stand on the top of the ladder even if all legs are on the ground

3 0
2 years ago
The student who performed this experiment in the question above wrote the following discussion: "The gas sample is known to cont
Sunny_sXe [5.5K]

Answer:

What was the experimental measurement of the gas?

Explanation:

6 0
2 years ago
A helium-filled balloon at 310.0 K and 1 atm, contains 0.05 g He, and has a volume of 1.21 L. It is placed in a freezer (T = 235
trapecia [35]

Answer : The value of \Delta E of the gas is 2.79 Joules.

Explanation :

First we have to calculate the moles of helium.

\text{Moles of helium}=\frac{\text{Mass of helium}}{\text{Molar mass of helium}}

Molar mass of helium = 4 g/mole

\text{Moles of helium}=\frac{0.05g}{4g/mole}=0.0125mole

Now we have to calculate the heat.

Formula used :

q=nc_p\Delta T\\\\q=nc_p(T_2-T_1)

where,

q = heat

n = number of moles of helium gas = 0.0125 mole

c_p = specific heat of helium = 20.8 J/mol.K

T_1 = initial temperature = 310.0 K

T_2 = final temperature = 235.0 K

Now put all the given values in the above formula, we get:

q=nc_p(T_2-T_1)

q=(0.0125mole)\times (20.8J/mol.K)\times (235.0-310.0)K

q=-19.5J

Now we have top calculate the work done.

Formula used :

w=-p\Delta V\\\\w=-p(V_2-V_1)

where,

w = work done

p = pressure of the gas = 1 atm

V_1 = initial volume = 1.21 L

V_2 = final volume = 0.99 L

Now put all the given values in the above formula, we get:

w=-p(V_2-V_1)

w=-(1atm)\times (0.99-1.21)L

w=0.22L.artm=0.22\times 101.3J=22.29J

conversion used : (1 L.atm = 101.3 J)

Now we  have to calculate the value of \Delta E of the gas.

\Delta E=q+w

\Delta E=(-19.5J)+22.29J

\Delta E=2.79J

Therefore, the value of \Delta E of the gas is 2.79 Joules.

3 0
3 years ago
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