Uhh how was your day or how is it going
Answer : The correct option is, (a) paramagnetic with two unpaired electrons.
Explanation :
According to the molecular orbital theory, the general molecular orbital configuration will be,
![(\sigma_{1s}),(\sigma_{1s}^*),(\sigma_{2s}),(\sigma_{2s}^*),(\sigma_{2p_z}),[(\pi_{2p_x})=(\pi_{2p_y})],[(\pi_{2p_x}^*)=(\pi_{2p_y}^*)],(\sigma_{2p_z}^*)](https://tex.z-dn.net/?f=%28%5Csigma_%7B1s%7D%29%2C%28%5Csigma_%7B1s%7D%5E%2A%29%2C%28%5Csigma_%7B2s%7D%29%2C%28%5Csigma_%7B2s%7D%5E%2A%29%2C%28%5Csigma_%7B2p_z%7D%29%2C%5B%28%5Cpi_%7B2p_x%7D%29%3D%28%5Cpi_%7B2p_y%7D%29%5D%2C%5B%28%5Cpi_%7B2p_x%7D%5E%2A%29%3D%28%5Cpi_%7B2p_y%7D%5E%2A%29%5D%2C%28%5Csigma_%7B2p_z%7D%5E%2A%29)
As there are 14 electrons present in the given configuration.
The molecular orbital configuration of molecule will be,
![(\sigma_{1s})^2,(\sigma_{1s}^*)^2,(\sigma_{2s})^2,(\sigma_{2s}^*)^2,(\sigma_{2p_z})^2,[(\pi_{2p_x})^1=(\pi_{2p_y})^1],[(\pi_{2p_x}^*)^0=(\pi_{2p_y}^*)^0],(\sigma_{2p_z}^*)^0](https://tex.z-dn.net/?f=%28%5Csigma_%7B1s%7D%29%5E2%2C%28%5Csigma_%7B1s%7D%5E%2A%29%5E2%2C%28%5Csigma_%7B2s%7D%29%5E2%2C%28%5Csigma_%7B2s%7D%5E%2A%29%5E2%2C%28%5Csigma_%7B2p_z%7D%29%5E2%2C%5B%28%5Cpi_%7B2p_x%7D%29%5E1%3D%28%5Cpi_%7B2p_y%7D%29%5E1%5D%2C%5B%28%5Cpi_%7B2p_x%7D%5E%2A%29%5E0%3D%28%5Cpi_%7B2p_y%7D%5E%2A%29%5E0%5D%2C%28%5Csigma_%7B2p_z%7D%5E%2A%29%5E0)
The number of unpaired electron in the given configuration is, 2. So, this is paramagnetic. That means, more the number of unpaired electrons, more paramagnetic.
Hence, the correct option is, (a) paramagnetic with two unpaired electrons.
Answer:
1Au(s) + 3HNO₃(aq) + 4HCl(aq) → 1HAuCl₄(aq) + 3NO₂(g) + 3H₂O(l)
The function of HCl is oxidize the gold.
Explanation:
It is possible to balance the reaction seeing each compound as a variable and take an equation for each atom, thus:
Au(s) + HNO₃(aq) + HCl(aq) → HAuCl₄(aq) + NO₂(g) + H₂O(l)
a + b + c = d + e + f
Au: a = d <em>(1)</em>
H: b + c = d + 2f <em>(2)</em>
N: b = e <em>(3)</em>
O: 3b = 2e + f <em>(4)</em>
Cl = c = 4d <em>(5)</em>
Assuming <em><u>a = 1</u></em>:
<em><u>1 = d</u></em> <em>(1)</em>
<u><em>c = 4</em></u> <em>(5)</em>
b + 3 = 2f <em>(2)</em>
3b = 2e + f <em>(4)</em>
As b = e:
b = f <em>(4)</em>
<em><u>f = 3</u></em>; <em><u>b = 3</u></em>; <em><u>e = 3</u></em>
Thus, balanced reaction is:
1Au(s) + 3HNO₃(aq) + 4HCl(aq) → 1HAuCl₄(aq) + 3NO₂(g) + 3H₂O(l)
<em>The function of HCl is oxidize the gold</em> that before reaction is Au⁰ and afte ris Au⁺³
I hope it helps!
Answer:
<h3>The answer is 0 kgm/s</h3>
Explanation:
The momentum of an object can be found by using the formula
<h3>momentum = mass × velocity</h3>
From the question
mass = 1000 kg
Since the car is sitting at rest it has no velocity that's
velocity = 0 m/s
So we have
momentum = 1000 × 0
We have the final answer as
<h3>0 kgm/s</h3>
Hope this helps you
International Union of Pure and Applied Chemistry