Question

19. What is sthe mass of 6.02 x 1024 atoms

Answer 1

The mass of magnesium in $6.02 \times 10^{24}$ atoms is 240 g.

Answer: Option A

Explanation:

First, we have to convert the atoms to moles of magnesium.

We know that $6.02 \times 10^{24}$ atoms are present in 1 mole of magnesium. So,

    $\text { 1 atom }=\frac{1}{6.02 \times 10^{24}} \text { moles }$

    $6.02 \times 10^{24} \text { atoms }=\frac{6.02 \times 10^{24}}{6.02 \times 10^{23}} \text { moles }=10 \text { moles }$

Thus,

     $Mass of M g= molar mass of M g \times No. of moles of M g$

     $\text { Mass of } M g=24 \times 10=240 g$

Thus, 240 g of Magnesium is present in $6.02 \times 10^{24}$ atoms.