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2 years ago

Which of the following is not a valid set of quantum numbers

Chemistry

2 answers:

zhuklara [117]2 years ago

7 0

Answer: C. n = 3, l = 3, m = 3

Explanation:

1. Principle Quantum Numbers: This quantum number describes the size of the orbital. It is represented by n. n = 1,2,3,4....

2. Azimuthal Quantum Number: This quantum number describes the shape of the orbital. It is represented as 'l'. The value of l ranges from 0 to (n-1). For l = 0,1,2,3... the orbitals are s, p, d, f...

3. Magnetic Quantum Number: This quantum number describes the orientation of the orbitals. It is represented as $m_l$ . The value of this quantum number ranges from $(-l\text{ to }+l)$ . When l = 2, the value of $m_l$ will be -2, -1, 0, +1, +2.

A. n = 2, l = 1 , m = 0 is possible.

B. n = 1, l = 0, m = 0 is possible.

C. n = 3, l = 3, m = 3 is not possible as for n = 3, l = 0, 1 and 2 and m = 0,+1, +2, -1 and -2.

ASHA 777 [7]2 years ago

3 0

I believe the answer is C, n = 3, l = 3, m = 3. The magnetic quantum number, or

ml, can only take values that range from −l to +l, as you can see in the table above.

For option C), the angular momentum quantum number of equal to ++2, which means that ml can have a maximum value of +2. Since it is given as having a value of +3**, this set of quantum numbers is not a valid one.

The other three sets are valid and can correctly describe an electron.

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Refer to the periodic table tool and write the electron configurations of the following elements in both long and short terms

ahrayia [7]

Answer:-

Carbon

[He] 2s2 2p2

1s2 2s2 2p2.

potassium

[Ar] 4s1.

1s2 2s2 2p6 3s2 3p6 4s1

Explanation:-

For writing the short form of the electronic configuration we look for the nearest noble gas with atomic number less than the element in question. We subtract the atomic number of that noble gas from the atomic number of the element in question.

The extra electrons we then assign normally starting with using the row after the noble gas ends. We write the name of that noble gas in [brackets] and then write the electronic configuration.

For carbon with Z = 6 the nearest noble gas is Helium. It has the atomic number 2. Subtracting 6 – 2 we get 4 electrons. Helium lies in 1st row. Starting with 2, we get 2s2 2p2.

So the short term electronic configuration is [He] 2s2 2p2

Similarly, for potassium with Z = 19 the nearest noble gas is Argon. It has the atomic number 18. Subtracting 19-18 we get 1 electron. Argon lies in 3rd row. Starting with 4, we get 4s1.

So the short electronic configuration is [Ar] 4s1.

For long term electronic configuration we must write the electronic configuration of the noble gas as well.

So for Carbon it is 1s2 2s2 2p2.

For potassium it is 1s2 2s2 2p6 3s2 3p6 4s1

5 0

2 years ago

Balance this equation. If a coefficient of "1" is required, choose "blank" for that box.

Kitty [74]

Answer: 2 C2H4 + 6 O2 => 4 CO2 + 4 H2O

Explanation:The coefficient are as follows: 2: 6: 4: 4

Each atom on the reactant and product side are equal.

Reactant Product

C 2x2 = 4 4x1 = 4

H 2x4 = 8 4x2 = 8

O 6x2 = 12 (4x2) + 4 = 12

7 0

3 years ago

At pH= 8, which species is most likely to predominate in solution? pKa (-NH3+) = 9.9, pKa (-COOH) = 2.3

PtichkaEL [24]

Answer:

The NH3 + with a PKa = 9.9

Explanation:

The Pka is a mathematical expression to express the dissociation grade of a substance in a solution, that means with a substance with a pKa small is a strong acid, and in this case since the solution pH is 8, that mean that the substance with high pKa ( lower acid strength) will predominate in a pH of 8.

7 0

3 years ago

If you don't keep giving a car gas, the car will eventually stop. *

Strike441 [17]

Answer:

newtons 2nd law is the answer

3 0

3 years ago

When phosphorus reacts with chlorine, phosphorus trichloride is formed according to the following equation: ___P4(s) ___Cl2(g) →

Slav-nsk [51]

Answer:

P4 + 6Cl2 ------> 4PCl3

145.59 g of Cl.

Explanation:

First to all, let's balance the equation. The principle for balance an equation, try to see this like a balance of two plates. You need to have the same numbers of atoms of both sides of the plates to equilibrate the balance.

In this case, we have 4 atoms of P, 2 of Cl on one side, and for the other side we have 1 atom of P and 3 of chlorine.

To balance this, we balance first the P on the right side putting a leading 4, and we have 4PCl3.

Now this 4, is also added to the Cl, and it's multiplied, so we have 12 Cl in total on the right side. To balance this, we put a leading 6 on the left side in the Cl.

The final balanced equation would be

P4 + 6Cl2 ------> 4PCl3

Now that we have the balanced equation, let's calculate the grams of Cl needed:

In this case, first, let's calculate the mole of P used in the 21.2 g. We need the atomic weight of P, which is 30.97 g/mol and the Cl is 35.45 g/mol

moles of P = g/AW = 21.2 / 30.97 = 0.6845 moles

With the balanced equation, we can do a relation between P and Cl.

If 1 mole P reacts with 6 moles of Cl,

then 0.6845 mole P reacts with X moles of Cl.

Solving for X:

X = moles of Cl = 0.6845 * 6 = 4.107 moles

Finally for the grams of Cl:

g = 4.107 * 35.45 = 145.59 g of Cl.

4 0

3 years ago