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kherson [118]
3 years ago
11

The element bromine is a reddish-brown liquid at room temperature, with a density of 3.103g/mL. What is the mass, in grams, of 1

9.8 ML of bro mine? Use the formula
D=M/V (where D equals density, M am equals mass, V equals volume).
Chemistry
1 answer:
Anastaziya [24]3 years ago
6 0
The element bromine is not a reddish-brown liquid. Liquid is the substance bromine.

M=DV

M=3.103 g/mL * 19.8 mL = 61.44 g
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Cecil writes the equation for the reaction of hydrogen and oxygen below.
Wittaler [7]

Answer:

C) to show that atoms are conserved in chemical reactions

Explanation:

When writing a chemical reaction, we should always consider the Mass Conservation Law, which basically states that; in an isolated system; the total mass should remain constant, this is, the total mass of the reactives should be equal to the total mass of the products

For this case, we should add the apporpiate coefficients in order to be in compliance with this law:

2H₂ + O₂ → 2H₂O

So, we can check the above statement:

For reactives (left side):

4H

2O

For product (right side):

4H

2O

5 0
3 years ago
Its gelatin and a fruit cup the same (its for a project)
gizmo_the_mogwai [7]

Answer:

No

Explanation:

Gelatin is a substance that makes jello, and a fruit cup is a cup full of fruit

6 0
2 years ago
Read 2 more answers
Given pH = 3.50 Find: [H3O+] and [OH-] Is this acidic, basic or neutral?
lys-0071 [83]

Answer:

Explanation:

Given parameters:

           pH = 3.50

Unknown:

    concentration of [H₃0⁺] = ?

    concentration of [OH⁻] = ?

Solution:

In order to find the unknown, we use some simple expressions which best explains the pH scale and the equilibrium systems of aqueous solutions.

         pH = -log₁₀[H₃O⁺]

         [H₃O⁺] = inverse log₁₀ (-pH) = 10^{-pH} = 10^{-3.5}

          [H₃O⁺] = 3.2 x 10⁻⁴moldm⁻³

       

For the  [OH⁻]:

       we use : pOH = -log₁₀ [OH⁻]

     Recall: pOH + pH = 14

                  pOH = 14 - pH = 14 - 3.5 = 10.5

  Now we plug the value of pOH into pOH = -log₁₀ [OH⁻]

                                   [OH⁻] = 10^{-pOH}

                        [OH⁻] = 10^{-10.5} = 3.2 x 10⁻¹¹moldm⁻³

The solution is acidic as the concentration of H₃0⁺ is more than that of the OH⁻ ions.

                   

8 0
3 years ago
Hydrogen gas is collected over water at 21 degrees Celsius. At 21 degrees Celsius the vapor pressure of water is 18.7 torr. If t
Alinara [238K]

Answer : The pressure of hydrogen gas is, 739.3 torr

Explanation :

As we are given:

Vapor pressure of water = 18.7 torr

Barometric pressure = 758 torr

Now we have to calculate the pressure of hydrogen gas.

Pressure of hydrogen gas = Barometric pressure - Vapor pressure of water

Pressure of hydrogen gas = 758 torr - 18.7 torr

Pressure of hydrogen gas = 739.3 torr

Therefore, the pressure of hydrogen gas is, 739.3 torr

3 0
3 years ago
**PLEASE ANSWER QUICK, I'LL GIVE BRAINLIEST TO THE RIGHT ANSWER !!**
rewona [7]

Answer:

c

Explanation:

the correct answer would be answer c

6 0
2 years ago
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