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Oliga [24]
3 years ago
12

A farmer will build a rectangular pen for his sheep. a wall will form one side of the pen. the farmer has 28 m of fencing to for

m the other three sides. the farmer plans to build the pen so that it has its maximum possible area. what will be the dimensions of the farmer’s sheep pen? enter your answers in the boxes.
_ m by _ m

Mathematics
1 answer:
Pavlova-9 [17]3 years ago
3 0

I took the quiz and this what the answer, I hope this help future people that had the same question.

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stiks02 [169]
For number 4, the midpoint is M, so the lengths of the 2 segments are half of the whole. PM and MQ are 11.

For number 5, TM and MS are 7.5.

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What does 10 = 4y equal to
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Read 2 more answers
What is the solution to the equation? 10y+11=25−3y Enter your answer in the box. y =
stiv31 [10]

Answer:

Interpreting as: 10y+11=25-3y

Input:

10 y + 11 = 25 - 3 y

8 0
3 years ago
In 1960, the population of a town was 14 thousand people. Over the course of the next 50 years, the town grew at a rate of 30 pe
andre [41]

SOLUTIONS

Given: Assume y is the population

\begin{gathered} t=0=1960,y=14030 \\ t=1=1961,y=14060 \\ so\text{ b = 14000} \\ so\text{ k = 30} \end{gathered}

The town grow at the rate of 30 people per year.

y=kt+14000y=30t+14000

(A) The population predicted to be in 2030 will be

\begin{gathered} 2030-1960=70 \\ y=30k+14000 \\ y=30(70)+14000 \\ y=2100+14000 \\ y=16100people \end{gathered}

(B) so when y = 15000, find t

\begin{gathered} y=15000 \\ y=30t+14000 \\ 15000=30t+14000 \\ 15000-14000=30t \\ 1000=30t \\ t=\frac{1000}{30} \\ t\approx33 \\ t=1960+33 \\ t=1993 \end{gathered}

3 0
1 year ago
3600 dollars is placed in an account with an annual interest rate of 9%. How much will be in the account after 25 years, to the
Mnenie [13.5K]
Assuming the interest is simple interest, as opposed to compound interest,

\bf ~~~~~~ \textit{Simple Interest Earned Amount}\\\\
A=P(1+rt)\qquad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to& \$3600\\
r=rate\to 9\%\to \frac{9}{100}\to &0.09\\
t=years\to &25
\end{cases}
\\\\\\
A=3600(1+0.09\cdot 25)\implies 3600(3.25)
3 0
3 years ago
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