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Andrew [12]
3 years ago
6

Extra points! Thank you!

Mathematics
1 answer:
Leni [432]3 years ago
7 0

Answer:

we have 2 real solutions

Step-by-step explanation:

ax^2 + bx+c

discriminant

b^2-4ac

6x=-2x^2-3

subtract 6x from each side

0 = -2x^2 -6x-3

a= -2

b=-6

c=-3

b^2-4ac = (-6)^2 - 4(-2) (-3)

                36 - 24

                   12



if > 0 2 real solutions

= 0    1 real solution

 < 0 2 complex solution


since 12 > 0 we have 2 real solutions

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