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Alexus [3.1K]
3 years ago
7

A truck can be rented from Company for 50 dollars a day plus 0.50 per mile. Company B charges 30 dollars a day plus 0.90 per mil

e to rent the same truck. Find the number of miles in a day at which the rental costs for company A and company B are the same.
Mathematics
1 answer:
kirill115 [55]3 years ago
7 0

Answer:

no company a gets 3 miles company b gets 5 miles

Step-by-step explanation:

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Use transformations to solve the equation <br> y- 0.6= -1.8
Anestetic [448]

Answer:

The answer is y = -1.2

Step-by-step explanation:

You can solve this by simply adding 0.6 to both sides of the equation.

y - 0.6 = -1.8

y = -1.2

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Igoryamba
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Ecuación de la hipérbola con centro en (0;0), focos en abrir paréntesis 0 coma espacio menos raíz cuadrada de 28 cerrar paréntes
yaroslaw [1]

Answer:

\frac{y^{2}}{25}-\frac{x^{2}}{3}=1

Step-by-step explanation:

Para resolver este problema debemos tomar en cuenta los datos que nos dan y la ecuación de una hipérbola. Comencemos con los datos:

centro: (0,0)

focos: (0,-\sqrt{28}),(0,\sqrt{28})

eje conjugado = 2\sqrt{3}

por los focos podemos ver que la hipérbola se dirige hacia el eje y, por lo que debemos tomar la siguiente forma de la ecuación de la parábola:

\frac{y^{2}}{a^{2}}+\frac{x^{2}}{b^{2}}=1

de los focos podemos obtener que:

c=\sqrt{28}

y del eje conjugado podemos saber que al dividir la longitud del eje conjugado dentro de 2 obtenemos b, así que:

b=\sqrt{3}

podemos utilizar la siguiente fórmula para obtener a:

c^{2}-a^{2}=b^{2}

si despejamos a en la ecuación obtenemos lo siguiente:

a=\sqrt{c^{2}-b^{2}}

ahora podemos sustituir los valores:

a=\sqrt{(\sqrt{28})^{2}-(\sqrt{3})^{2}}

a=\sqrt{28-3}

a=\sqrt{25}

a=5

así que media vez conozcamos a, podemos sustituir los datos en la ecuación de la hipérbola así que obtenemos lo siguiente:

\frac{y^{2}}{a^{2}}+\frac{x^{2}}{b^{2}}=1

\frac{y^{2}}{(5)^{2}}+\frac{x^{2}}{(\sqrt{3})^{2}}=1

\frac{y^{2}}{25}+\frac{x^{2}}{3}=1

si graficamos la hipérbola, queda como en el documento adjunto.

7 0
3 years ago
F(x) = x2 + 10<br> What is the average rate of chan<br> hange of f over the interval [-2, -1]?
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