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Tasya [4]
3 years ago
5

z scores are useful because they:a. allow us to convert raw scores to mean scores, compare scores from different samples, and tr

ansform populations into samples.b. transform linear scores into nonlinear scores, convert nonlinear scores back into linear scores, and allow us to obtain comparisons between nonlinear and linear scores.c. give us an understanding of where a score falls in relation to the mean of its underlying population, allow comparisons to be made between scores from different distributions, and permit the transformation of z scores into percentiles.d. reduce the probability of Type I and Type II errors, allow us to compare raw scores with standard scores, and permit the transformation of raw scores into percentiles.
Mathematics
1 answer:
Alla [95]3 years ago
3 0

Answer:

they give us a sense of where a score falls in relation to the mean of its population (in terms of standard deviation of its population), 2) they allow us to compare scores from different distributions, and 3) they can be transformed into percentiles.

Step-by-step explanation:

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Step2247 [10]

Answer:

Percent: 20%

Fraction: 1/5

Decimal: 0.20

Step-by-step explanation:

8:40*100 =

( 8*100):40 =

800:40 = 20%

Percent to fraction:

20%=20/100

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=0.2×10/10

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A similarity transformation maps `Delta`ABC to `Delta`JKL. The measure of `/_A` of preimage `Delta`ABC is 105°. The scale factor
RoseWind [281]

Please note that dilation does not affect angles. Thus, if an image is dilated the angle remains the same and does not change.

Therefore, even if \Delta ABC is dilated to \Delta JKL by a factor of 1.5 (or by any factor for that matter), the linear dimensions of the original triangle \Delta ABC will either get stretched or get shrunk by a factor of 1.5 but the angles of the original triangle will not be affected in any case.

Please note that this is true for all two dimensional geometric shapes.

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3 years ago
g 1.32 Two points on a sphere of radius 3 are given as P1(3,0,30) and P2(3,45,45): (a) Find the position vectors of P1 and P2. (
Rama09 [41]

Answer:

a) P.V  of is OP₁ = [ 1.5i + 0j + 2.6k ],   P.V  of is OP₂ = [ 1.5i + 1.5j + 2.12k ]

b) Vector connecting P₁ to P₂ is [ 0i + 1.5j + 0.48k ]  

c) cylindrical coordinates are (1.5, π/2, 0.48)

Step-by-step explanation:

Given that;

r = 3

P₁ ( 3, 0°, 30° ),   P₂ ( 3, 45°, 45° )

a)

P.V of P₁

x = rcos∅sin∅ = 3(cos0°) ( sin30°) = (3 × 1 × 0.5) = 1.5

y = rsin∅sin∅  = 3(sin0°) (sin30°)   = (3 × 0 × 0.5) = 0

z = rcos∅        = 3(cos30°)             = ( 3 × 0.866)  = 2.6

∴ P.V  of is OP₁ = [ 1.5i + 0j + 2.6k ]

P.V of P₂

x = rcos∅sin∅ = 3(cos45°) ( sin45°) = (3 × 0.7071 × 0.7071) = 1.5

y = rsin∅sin∅  = 3(sin45°) (sin45°)   = (3 × 0.7071 × 0.7071) = 1.5

z = rcos∅        = 3(cos45°)                 = ( 3 × 0.7071)            = 2.12

∴ P.V  of is OP₂ = [ 1.5i + 1.5j + 2.12k ]

b)

Vector connecting P₁ to P₂ is given by

OP₂ - OP₁ = [ 1.5i + 1.5j + 2.12k ] - [ 1.5i + 0j + 2.6k ]

= [ 0i + 1.5j + 0.48k ]  

c)

P₁P₂ → = [ 0i + 1.5j + 0.48k ]  = [ 1.5j + 0.48k ]  

so in a cylindrical coordinate, it should be

r = √(o² + 1.5²) = 1.5

∅ = tan⁻¹[y/π] = π/2

z = 0.48

cylindrical coordinates are (1.5, π/2, 0.48)

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