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3 years ago

How big is the image produced by the periscope compared to the size of the object

Physics

1 answer:

ipn [44]3 years ago

8 0

As long as both mirrors are set at 45% and the same size then you see the same as is reflected in the upper mirror 

Put a lens in the middle of the tube 

? 

We use mirrors when we drive cars ect 

Normally they are set across from a concealed entrance or one that is hard to see both ways like the inside of a hairpin bend. Sometimes only to help in one direction. 

Sonar which is sound waves that are sent out at a set rate then reflected by objects. The longer the gap between the two the further away it is, They still use periscopes to target boats though. 

The periscope can only reflect what is outside so if you could see it because there is enough light then Yes. If you could not see it because it is dark then No unless you get into Info-Red light or Image Intensifying systems as well

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One violin creates a sound whose intensity level is 60dB. Find the intensity level of 16 violins, each playing at this intensity

Yanka [14]

Answer:

72.04 dB.

Explanation:

The intensity level of 60dB corresponds to the sound intensity $I$ given by the equation

$60dB = 10log(\dfrac{I}{I_0} )$

where $I_0 = 1*10^{-12}W/m^2$

solving for $I$ we get:

$6 = log(\dfrac{I}{I_0} )$

$10^6 =\dfrac{I}{1*10^{-12}}$

$\boxed{I = 1*10^{-6} W/m^2}$

Now, when 16 violins are playing the intensity $I$ becomes

${I = 16(1*10^{-6} W/m^2)$

which on the decibel scale gives

$dB = 10log(\dfrac{16*10^{-6}}{1*10^{-12}} )$

$dB = 72.04\: dB$ .

Thus, playing 16 violins together gives the intensity level of 72 dB.

8 0

3 years ago

A certain part of a computer chip has a length of 1.5 micrometers. How many meters is this ?

Alchen [17]

When you're working with units of measure, "micro" almost always means "millionth", or 1 x 10⁻⁶ . And that's exactly the case in this example.

"1.5 micrometer" = 1.5 millionths of a meter, or 1.5 x 10⁻⁶ meter.

4 0

3 years ago

An object in space has altitude of 2210 km, velocity of 7000 m/s and flight path angle of 20 degrees. Find the eccentricity, sem

Dmitry [639]

Answer:

Eccentricity = 0.0557

Semi-major axis = 9,095 km

Angular momentum/mass = 60,116 $\frac{km^{2} }{Sec}$

Kinetic energies/mass = 24,500 KJ

Potential energies/mass = 21,673 KJ

Explanation:

Eccentricity

To find the eccentricity use the following formula

Eccentricity = [ Altitude from the earth x ( $Velocity^{2}$ / Gravitational parameter for the Earth ) ] - 1

Where

Altitude from the earth radius = Radius of the earth + Altitude of the earth from radius = 6,378 km + 2,210 km = 8,588 km

Velocity = 7,000 m/s

Gravitational parameter for the Earth = 3.986004418 × $10^{14}$

Eccentricity = ?

Placing values in the formula

Eccentricity = [ ( 8,588 km x 1000 ) x ( $7000^{2}$ / 3.986004418 × $10^{14}$ ) ] - 1

Eccentricity = 0.0557

Semi-major axis

Total Distance = Semi-major axis x ( 1 - Eccentricity )

Where

Total Distance = 8,588 km

Eccentricity = 0.0557

8,588 x 1,000 m = Semi-major axis x ( 1 - 0.0557 )

8,588,000 m = Semi-major axis x 0.9443

Semi-major axis = 8,588,000 m / 0.9443

Semi-major axis = 9,094,567.40 m

Semi-major axis = 9,094.56740 km

Semi-major axis = 9,095 km

Angular momentum/mass

L = MVR

L/M = VR

Where

V = Velocity = $\frac{7,000 m/s}{1000}$ = 7 km/s

R = Total Radius = Radius of Earth + Altitude = 6,378 km + 2,210 km = 8,588 km

Placing values in the formula

L/M = 7 km/s x 8,588 km = 60,116 $\frac{km^{2} }{Sec}$

Kinetic energies/mass

Ke = I $W^{2}$

Ke = $\frac{1}{2} mr^{2}$ $W^{2}$ ( Where I = $mr^{2}$ )

$\frac{ke}{m}$ = $\frac{r^2}{2}$ $W^{2}$

$\frac{ke}{m}$ = $\frac{r^2}{2}$ $\frac{V^2}{r^2}$ ( $W^{2}$ = $\frac{V^2}{r^2}$ )

$\frac{ke}{m}$ = $\frac{V^2}{2}$

$\frac{ke}{m}$ = $\frac{7000^2}{2}$

$\frac{ke}{m}$ = 24,500,000 J

$\frac{ke}{m}$ = 24,500 KJ

Potential energies/mass

PE = mgh

$\frac{PE}{m}$ = gh

Where

g = 9.807 $\frac{m}{s^2}$

h = 2,210 km x 1,000 = 2,210,000 m

Placing values in the formula

$\frac{PE}{m}$ = 9.807 $\frac{m}{s^2}$ x 2,210,000 m

$\frac{PE}{m}$ = 21,673,470 J

$\frac{PE}{m}$ = 21,673.470 KJ

$\frac{PE}{m}$ = 21,673 KJ

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3 years ago

The three vehicles shown below are all traveling at a speed of 15 m/s, but only the pickup truck has a changing velocity.

sweet [91]

Answer: is traveling on a curve in the road

Explanation:

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2 years ago

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Why does a plane move even when the wind is pushing against it?

boyakko [2]

A plane has more mass in it. Also, the engine is very strong which it makes the plane able to push through the wind. When the wind is pushing, it goes by it because of the engine.

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3 years ago

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