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3 years ago

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You are on a hike in the mountains. You have 3.79 km left to go before your next campsite. The sun will set in 6.93 h. What aver

age speed must you walk to get to camp at sunset? Answer in units of km/h

1 answer:

Nadya [2.5K]3 years ago

7 0

The average speed is equal to the total distance covered in a specific interval of time. Since we are given with the information on distance and time, all we have to do is divide them.

Average speed = 3.79 km/6.93 h = 0.547 km/h

Hence, you should not have a speed less than 0.547 km/h if you want to catch the sunset.

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In reading the instruction manual that came with your garagedoor opener, you see that the transmitter unit in your car produces

iVinArrow [24]

Answer:

0.09221 V/m

Explanation:

$\mu_0$ = Vacuum permeability = $4\pi \times 10^{-7}\ H/m$

P = Power of transmitter = 250 mW

r = Distance to source = 42 m

c = Speed of light = $3\times 10^8\ m/s$

$E_0$ = Electric field amplitude

Intensity of a wave is given by

$I=\frac{P}{4\pi r^2}\\\Rightarrow I=\frac{250\times 10^{-3}}{4\pi \times 42^2}\\\Rightarrow I=1.12779\times 10^{-5}\ W/m^2$

Intensity is also given by

$I=\frac{E_0^2}{2\mu_0 c}\\\Rightarrow E_0=\sqrt{I2\mu_0 c}\\\Rightarrow E_0=\sqrt{1.12779\times 10^{-5}\times 2\times 4\pi \times 10^{-7}\times 3\times 10^8}\\\Rightarrow E_0=0.09221\ V/m$

The electric field amplitude at the receiver when it first fails is 0.09221 V/m

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4 years ago

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Answer:

Explanation:

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Starting with a new moon, name the phases the moon will pass through before the next new moon.

ipn [44]

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3 years ago

A heavy solid disk rotating freely and slowed only by friction applied at its outer edge takes 120 seconds to come to a stop.

alisha [4.7K]

Answer:

The time is 16 min.

Explanation:

Given that,

Time = 120 sec

We need to calculate the moment of inertia

Using formula of moment of inertia

$I=\dfrac{1}{2}MR^2$

If the disk had twice the radius and twice the mass

The new moment of inertia

$I'=\dfrac{1}{2}\times2M\times(2R)^2$

$I'=8I$

We know,

The torque is

$\tau=F\times R$

We need to calculate the initial rotation acceleration

Using formula of acceleration

$\alpha=\dfrac{\tau}{I}$

Put the value in to the formula

$\alpha=\dfrac{F\times R}{\dfrac{1}{2}MR^2}$

$\alpha=\dfrac{2F}{MR}$

We need to calculate the new rotation acceleration

Using formula of acceleration

$\alpha'=\dfrac{\tau}{I'}$

Put the value in to the formula

$\alpha=\dfrac{F\times R}{8\times\dfrac{1}{2}MR^2}$

$\alpha=\dfrac{2F}{8MR}$

$\alpha=\dfrac{\alpha}{8}$

Rotation speed is same.

We need to calculate the time

Using formula angular velocity

$\Omega=\omega'$

$\alpha\time t=\alpha'\times t'$

Put the value into the formula

$\alpha\times120=\dfrac{\alpha}{8}\times t'$

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Hence, The time is 16 min.

5 0

3 years ago

395,000 meters in 9000

marta [7]

Answer:

43.88 meters per second

Explanation:

The computation of the speed is shown below:

As we know that

$Speed = \frac{Distance}{time}$

where,

Distance is 395,000 meters

Time is 9,000 seconds

Now placing these values to the formula

So, the speed is

$= \frac{395,000}{9,000}$

= 43.88 meters per second

As speed shows the relation between the distance and time and the same is to be considered i.e by applying the formula

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3 years ago