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3 years ago

Baking cake is what a physical or chemical change

Physics

1 answer:

xenn [34]3 years ago

8 0

Answer:

It's a chemical change.

Explanation:

The ingredients will react together once mixed and heated. Also the ingredients can not be pulled apart.

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Calculate the mass (in SI units) of (a) a 160 lb human being; (b) a 1.9 lb cockatoo. Calculate the weight (in English units) of

kondaur [170]

Explanation:

1. Force applied on an object is given by :

F = W = mg

(a) A 160 lb human being, F = 160 lb

g = acceleration due to gravity, g = 32 ft/s²

$m=\dfrac{F}{g}$

$m=\dfrac{160\ lb}{32\ ft/s^2}$

m = 5 kg

(b) A 1.9 lb cockatoo, F = 1.9 lb

$m=\dfrac{F}{g}$

$m=\dfrac{1.9\ lb}{32\ ft/s^2}$

m = 0.059 kg

2. (a) A 2300 kg rhinoceros, m = 2300 kg

$W=2300\ kg\times 32\ ft/s^2=73600\ lb$

(b) A 22 g song sparrow, m = 22 g = 0.022 kg

$W=0.022\ kg\times 32\ ft/s^2=0.704\ lb$

Hence, this is the required solution.

5 0

3 years ago

Two charges, q1 and q2, are separated by a certain distance r. if the magnitudes of the charges are halved and their separation

vazorg [7]

The electrical force between these two charges remains the same. In coulomb’s law, it states that the magnitude of two charges (product of two charges) is inversely proportional to the square of the distance. Since both the magnitude and the distance are halved, therefore, the change in both quantities will have no effect in the value of electrical force.

6 0

3 years ago

What determines the velocity of an object?

BARSIC [14]

I think it’s A not 100% sure

4 0

2 years ago

Jacob is traveling at 5.00 m/s North. Jacob throws a ball with a velocity of 5.00 m/s South. Jacob throws the ball from a height

Nataly [62]

Answer:t=0.54 s

Explanation:

Given

Jacob is traveling 5 m/s in North direction

Jacob throw a ball with a in south direction with a velocity of 5 m/s

Ball is thrown in opposite direction of motion of car therefore it seems as if it is dropped from car as its net horizontal velocity is 5-5=0

Time taken by ball to reach ground

$s=ut+\frac{gt^2}{2}$

$1.45=0+\frac{9.81\times t^2}{2}$

$t^2=frac{2\times 1.45}{9.81}$

t=0.54 s

Motion of ball will be straight line

3 0

3 years ago

You are rushing to the train station to catch your morning commute. The train leaves the train station from rest with an acceler

Vanyuwa [196]

Answer:

a) t= 4.81 s,and t= 23.51.

b)d=6.88 m

c)v=4.8 m/s

Explanation:

Acceleration of train ,a= 0.6 m/s²

u = 0 m/s

Your speed ,V= 8.5 m/s

Lets take after t time he you catch the train

Distance travel by train in t time

$d=ut+\dfrac{1}{2}at^2$

$d=\dfrac{1}{2}\times 0.6\times t^2$ ----------1

d= V ( t- 4)

d= 8.5 ( t- 4) --------2

By equating equation 1 and 2

0.3 t² = 8.5 ( t- 4)

0.3 t² -8.5 t + 34 = 0

t= 4.81 s and t= 23.51

It means that you will catch train after t= 4.81 s,and t= 23.51.

t=23.51 sec means that you will catch the train after 23.51 sec also because acceleration of train is low.

Distance travel

d= 8.5 ( t- 4)

t= 4.81 s

d= 8.5 ( 4.81- 4) m

d=6.88 m

Lets speed = v

0.3 t² = v ( t- 4)

0.3 t² - v t + 4 v = 0

To have one solution

$D=\sqrt{b^2-4ac}$

D= 0 Should be zero.

v²- 4 x 0.3 x 4 v

v = 4 x 0.3 x 4

v=4.8 m/s

6 0

3 years ago