Answer:
METABALIOCO HURAN GURGER THGDY
Explanation:
Explanation:
Given parameters:
Distance = 15miles north = 24140.2m
Initial velocity = 0m/s
Final velocity = 4m/s
Unknown:
Speed, velocity and acceleration = ?
Solution:
The speed is the distance divide by time. It is a scalar quantity and has no directional attribute.
Speed =
The speed of the student is 4m/s
Velocity is the displacement divided by time. It is a vector quantity which specifies the direction and magnitude;
Velocity =
The velocity of the student is 4m/s due north
Acceleration is the change in velocity with time;
To find the acceleration, we use
v² = u² + 2as
v is the final velocity
u is the initial velocity
a is the acceleration
s is the distance
4² = 0² + 2x a x 24140.2
a = = 0.00033m/s²
Displacement is the total space between point a and b. For example, If I walk 3 times North, 6 times East, and 7 times North, what is the displacement? The answer is 10 because when I walked East there was on object blocking my way.
Given: Heat given to mercury (Q) = 100 J
Mass of mercury (m) = 80 g = 80 × 10⁻³ kg
Specific Heat capacity of mercury (c) = 138 J/kg°C
Let the rise of temperature be Δt
Formula Used: Q = mcΔt
Here, all alphabets are in their usual meanings.
Calculation:
Q = mcΔt
or, Δt = Q / mc
or, Δt = 100 J /[(80 × 10⁻³ kg)×(138 J/kg°C)]
or, Δt = 9.058 °C
or, Δt = 9.1 °C
Hence, the required increase in temperature will be 9.1 °C.