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3 years ago

Sin data cos data tan datacsc date sec data cot data

Mathematics

1 answer:

MAXImum [283]3 years ago

3 0

Answer:

See below.

Step-by-step explanation:

The first coordinate of the point is X = 7/25 and the second is Y = 24/25.

And r = SQR ROOT of (X² + Y²)

sin theta = y/r

cos theta = x/r

tan theta = y/x

csc theta= 1/sin theta = r/y

sec theta = 1/cos theta = r/x

cot theta = 1/tan theta = x/y

Just calculate them out.

Have a great day!

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There is a bag with only red marbles and blue marbles.

mote1985 [20]

Answer:

red marbles

Step-by-step explanation:

Since the formula is;

Probability = number of required outcome

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number of possible outcome

3/8. = x/56

8x. = 168

x. 21 ( number of blue marbles)

Therefore if the total marbles = 56 and 21 of the marbles are blue then to get the red marbles

= 56 - 21

= 35

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3 years ago

Find the midpoint m of the line segment joining the points p (-5,-3) = q and = (-1,-1)

babymother [125]

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1 year ago

Mya and ERIC WORK IN A BAKERY . MYA HAS 3 TIMEA AS MUCH FLOUR AS ERIC .MYA HAS 15.81LB OF FLOUR .USE THE EQUATION 3F = 15.81 TO

Pavel [41]

Answer:

5.27 lb

Step-by-step explanation:

Given that,

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3 years ago

The surface area of a cylinder is increasing at a rate of 9 pi square meters per hour. The height of the cylinder is fixed at 3

Alekssandra [29.7K]

Answer:

$9\pi \text{ cubic meters per hour}$

Step-by-step explanation:

Since, the surface area of a cylinder,

$A= 2\pi r^2 + 2\pi rh$ ................(1)

Where,

r = radius,

h = height,

If $A= 36\pi\text{ square meters}, h = 3\text{ meters}$

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$18 = r^2 + 3r$

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$r^2 + 6r - 3r - 18 = 0$ ( by middle term splitting )

$r(r+6)-3(r+6)=0$

$(r-3)(r+6)=0$

By zero product property,

r = 3 or r = - 6 ( not possible )

Thus, radius, r = 3 meters,

Now, differentiating equation (1) with respect to t ( time ),

$\frac{dA}{dt}= 4\pi r\frac{dr}{dt} +2\pi(r\frac{dh}{dt} + h\frac{dr}{dt})$

∵ h = constant, ⇒ dh/dt = 0,

$\frac{dA}{dt} = 4\pi r \frac{dr}{dt} +2\pi h \frac{dr}{dt}$

We have, $\frac{dA}{dt}=9\pi\text{ square meters per hour}, r = h = 3\text{ meters}$

$9\pi = 4\pi (3) \frac{dr}{dt}+2\pi (3)\frac{dr}{dt}$

$9\pi = (12\pi + 6\pi )\frac{dr}{dt}$

$9\pi = 18\pi \frac{dr}{dt}$

$\implies \frac{dr}{dt} =\frac{1}{2}\text{ meter per hour}$

Now,

Volume of a cylinder,

$V=\pi r^2 h$

Differentiating w. r. t. t,

$\frac{dV}{dt}=\pi ( r^2 \frac{dh}{dt}+h(2r)\frac{dr}{dt})=\pi ((3)(6) (\frac{1}{2})) = 9\pi \text{ cubic meters per hour}$

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3 years ago

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GuDViN [60]

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3 years ago

Sin data cos data tan datacsc date sec data cot data ​

Sin data cos data tan datacsc date sec data cot data