Proton mass = 1.00728 amu
neutron mass = 1.0086 amu
electron mass = 0.000549 amu
so the mass is :
(7 * 1.00728) - (7 * 1.0086) - (7 * 0.000549) - 14.003074
= 0.11235 amu
Answer:
Volume = 10 cm3
Density = 2.3g/cm3
Explanation:
volume:
30ml - 20ml = 10ml = 10cm3
density:
density = mass/volume
23/10
2.3g/cm3
To determine the empirical formula of the compound given, we need to determine the ratio of each element in the compound. To do that, we need to know the amount of carbon, hydrogen and oxygen atoms in the compound. We determine these from the given amounts of the products after burning.
Given:
2.5 g vanillin
5.79 g CO2
1.18 g H2O
Solution:
mol C = 5.79 g CO2 ( 1 mol CO2 / 44.01 g CO2) ( 1 mol C / 1 mol CO2) = 0.132 mol C
mol H = 1.18 g H2O ( 1 mol g H2O / 18.02 g H2O) ( 2 mol H / 1 mol H2O) = 0.131 mol H
We convert them into grams,
0.132 mol C (12.01 g / 1 mol) = 1.59 g
0.131 mol H (1.01 g / 1 mol) = 0.132 g
mass of C and H in vanillin = 1.722 g
mass of O = 2.5 - 1.722 = 0.778 g O
mol O = 0.778 g O ( 1 mol O / 16 g ) = 0.049 mol O
Dividing the number of moles of each element with the smallest value of number of mole, we will have the empirical formula:
moles ratio
C 0.132 / 0.049 2.69 x 3 = 8
H 0.131 / 0.049 2.67 x 3 = 8
O 0.049 / 0.049 1 x 3 = 3
The empirical formula would be C8H8O3.
Answer:
I think Acetone will be captured and cooled.
Explanation:
Distillation is a method of separation based on the difference in boiling point of two liquids.
The liquid that has a lower boiling point is first separated from the mixture. It vaporizes, cooled and collected before the liquid that has a higher boiling point.
In this case, acetone is captured and cooled before water since it has a boiling point of 56ºC and water has a boiling point of 100ºC.
Answer:
C6H12
Explanation:
Molar mass of C =12.0 H=1.0
12x + 2(1x) = 84
x = 6
so it should be C6H12