Answer:
B. 
Explanation:
The unit for rate is M/s while the unit for each molecule should be M. You can find the unit for k by putting the units for rate and the molecules into the equation
rate= k{X][Y]
M/s= k *
* 
k= (M/s) / (
)
k= 
You can also use this predetermined formula to solve this problem faster: k= 
Where n is the number of molecule. There are 3 molecule(2X and 1Y) so n=3, so
k= 
k=
=
= 
Answer:
large, released
Explanation:
As we know, fireworks contain l o t s of energy, even before the burst of colors release. So i think choice 3 is the answer.
i hope this helps :)
Use M x V = M' x V'
0.300 x V = 0.100 x 250
V = .......... ml
True because it doesn’t count as a full number
D. CuCl2 copper(2)chloride