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inessss [21]
3 years ago
5

Identify 6 examples of weathering (mechanical, chemical) in your environment such as (household, yard, street, cemetery, park, a

nd playground). Identify what type of weathering occurred. (Ex. Oxidation, dissolution/carbonation). Explain how each example occurred. Usea picture to show each example of the processe
Chemistry
2 answers:
Bogdan [553]3 years ago
4 0
Chemical weathering is when things get weathered chemically 
kirill115 [55]3 years ago
3 0
Chemical, water in metal, wood and water, aging and tree
mechanical, wind on house wind on tree dust and walls
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What is the mass, in grams, of 50.0L of N2 at STP?
vodka [1.7K]

Hey there!:

Molar mass N₂ = 28.0134 g/mol

28.0134 g ------------------- 22.4 L (at STP )

mass  N₂ -------------------- 50.0 L

mass N₂ = 50.0 x 28.0134 / 22.4

mass N₂ = 1400.67 / 22.4

mass N₂ = 62.529 g

Hope this helps!

6 0
3 years ago
How many quarts are in 0.15 ML
olganol [36]

Answer: divide by 946.353

= 1.58 x 10^-4 or 0.000159

Explanation:

7 0
2 years ago
A solution composed of 30.6g NH3 in 81.3g of H20. Calculate the mole fraction for NH3 and H20
irina [24]

Answer:

0.286 moles

Explanation:

i hope this is helpful for you

4 0
2 years ago
Read 2 more answers
Choose the reaction that represents the combustion of C6H12O2.
Leona [35]

Answer:

The answer to your question is:  letter D

Explanation:

In a combustion reaction, the reactants are always a molecule with Carbon that reacts with oxygen and the products are carbon dioxide and water.

According to the explanation, the only possible solution is:

a) C₆H₁₂O₂(l) ⇒ 6 C(s) + 6 H₂(g) + O₂(g)

b) Mg(s) + C₆H₁₂O₂(l) ⇒ MgC₆H₁₂O₂(aq)

c) 6 C(s) + 6 H₂(g) + O₂(g) ⇒ C₆H₁₂O₂(l)

d) C₆H₁₂O₂(l) + 8 O₂(g) ⇒ 6 CO₂(g) + 6 H₂O(g)

e) None of the above represent the combustion of C₆H₁₂O₂.

4 0
2 years ago
Read 2 more answers
Part A:
uranmaximum [27]

Answer:

Part A = The mass of sulfur is 6.228 grams

Part B = The mass of 1 silver atom is 1.79 * 10^-22 grams

Explanation:

Part A

Step 1: Data given

A mixture of carbon and sulfur has a mass of 9.0 g

Mass of the product = 27.1 grams

X = mass carbon

Y = mass sulfur

x + y = 9.0  grams

x = 9.0 - y

x(molar mass CO2/atomic mass C) + y(molar mass SO2/atomic mass S) = 22.6

(9 - y)*(44.01/12.01) + y(64.07/32.07)

(9-y)(3.664) + y(1.998)

32.976 - 3.664y + 1.998y = 22.6

-1.666y = -10.376

y = 6.228 = mass sulfur

x = 9.0 - 6.228 = 2.772 grams = mass C

The mass of sulfur is 6.228 grams

Part B

Calculate the mass, in grams, of a single silver atom (mAg = 107.87 amu ).

Calculate moles of 1 silver atom

Moles = 1/ 6.022*10^23

Moles = 1.66*10^-24 moles

Mass = moles * molar mass

Mass = 1.66*10 ^-24 moles *107.87

Mass = 1.79 * 10^-22 grams

The mass of 1 silver atom is 1.79 * 10^-22 grams

5 0
2 years ago
Read 2 more answers
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