The solution would be like this for this specific problem:
sin(θ°) = √(2)/2
θ° = 360°n + sin⁻¹(√(2)/2) and θ° = 360°n + 180° −
sin⁻¹(√(2)/2)
θ° = 360°n + 45° and θ° = 360°n + 135° where n∈ℤ
360°*0 + 45° = 45°
360°*0 + 135° = 135°
360°*1 + 45° = 405°
<span>sin(225°) = -√(2)/2
</span>225 has an angle where sin theta= -(sqrt2)/2 therefore, the value of theta
cannot be 225 degrees.
You mean -3/2 * -51/4???
use the calculator to multiply them and you will get 19.125
Answer:
1) b and m
2) m∠8=m∠6
3) 160°
4)x=60°
Step-by-step explanation:
1) all straight lines sum to 180°
subtract the angles given from 180°
the other angle for b is 25°, while the other angle for m is 155°
so we can see that the angles for both lines are the same, hence they are parallel.
2) ∠8 should be the same as ∠6, ∠10 should be the same as ∠3, ∠7 same as ∠5 and ∠9 same as ∠4
in the options we are only given '∠8 should be the same as ∠6' as the correct answer, so we take that.
3) from the image we can see that both horizontal lines are parallel to each other, so both angles on the lines should be same, so ∠CET would be (2x-16)°
(2x-16)°+(7x+20)°=180°
we get x=20(nearest whole number)
∠CED=7x+20=7(20)+20=160°
4) since we need to show that they are parallel,
(2x+30)°=(4x-90)°
2x-4x=-90-30
-2x=-120
x=60
we then plug the x value into the two equations, in which we get 150° for both the angles [2(60)+30=4(60)-90] ⇒ (150=150)
I hope u understand it the way I put it.
Answer:
Tens place
Step-by-step explanation:
Answer:
It falls to the left and falls to the right. You can use Geogebra. There you just type the formula and it makes graph from which you can see the directions