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Maru [420]
3 years ago
8

Rewrite 2x^2+13x+26/x+4 in the form q(x)+r(x)/b(x) . Then find q(x) and r(x).

Mathematics
2 answers:
sergey [27]3 years ago
8 0

Answer:

Q(x)= 2x+5

R(x)= 6

Step-by-step explanation:

natulia [17]3 years ago
6 0
We are dividing the polynomial 2x^{2} +13x+26 by x+4

notice that 2x^{2} is x times 2x,

so if we multiply (x+4) by 2x, which gives us 2 x^{2} +8x, we can 'separate' one 2 x^{2} +8x from 2x^{2} +13x+26  to get the following simplification:

\frac{2x^{2} +13x+26}{x+4}= \frac{ 2x^{2}+8 x}{x+4} + \frac{5x+26}{x+4}=2x+ \frac{5x+26}{x+4}

similarly we notice that 5x is x times 5, so if we multiply (x+4) by 5, we get 5x+20 so we can rewrite 

\frac{5x+26}{x+4}= \frac{5x+20}{x+4}+  \frac{6}{x+4}=5+\frac{6}{x+4}

\frac{6}{x+4} can not be simplified any further since the degree of 6, is smaller than the degree of x+4

combining our work, we have:

\frac{2x^{2} +13x+26}{x+4}=2x+5+\frac{6}{x+4}

Answer:

q(x)= 2x+5
r(x)=6
b(x)=x+4


Remark: we can solve the problem by long division or the division algorithm as well.
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3 years ago
A child from a class of 30 students is chosen to pick one of five prizes. How many outcomes are there
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Answer: 5?

Step-by-step explanation:

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4 0
3 years ago
I rent a gym for $150 for 30 students another time I rent the gym for $270 for 70 students I need to find a fixed rate
kirza4 [7]

Answer:

Fixed rate is $60.

Step-by-step explanation:

Let us consider per student charge be 'x'.

Let us consider fixed rate be 'b'

Given:

I rent a gym for $150 for 30 students.

So we can say that;

Total amount is equal to sum of number of students multiplied by per student charge and fixed rate.

framing in equation form we get;

30x+b=150 \ \ \ \ equation \ 1

Also Given:

another time I rent the gym for $270 for 70 students.

So we can say that;

Total amount is equal to sum of number of students multiplied by per student charge and fixed rate.

framing in equation form we get;

70x+b=270 \ \ \ \ equation \ 2

Now we will subtract equation 1 from equation 2 we get;

70x+b-(30x+b)=270-150\\\\70x+b-30x-b=120\\\\40x=120

Dividing both side by 40 we get;

\frac{40x}{40}=\frac{120}{40}\\\\x=\$3

Now we will substitute the value of x in equation 1 we get;

30x+b=150\\\\30\times3+b=150\\\\90+b=150\\\\b=150-90 =\$60

So we can say that the equation can be written as;

y =3x+60

Hence we can say that fixed rate is $60 and per student charge is $3.

3 0
3 years ago
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Find the sum of (3x2 + 16x + 9) and (−16x − 12).
IgorC [24]
<span>3x^2 + 16x + 9 −16x − 12
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4 0
3 years ago
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sattari [20]

Answer:

27

Step-by-step explanation:

If you 9 times 3 u get 27

7 0
3 years ago
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