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kozerog [31]
2 years ago
13

A comparison of two quantities

Mathematics
1 answer:
dybincka [34]2 years ago
6 0

A comparison of two quantities is called a ratio

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A regular pentagon has an apothem of 7.3 inches and a perimeter of 53 inches. What is the area of the pentagon? Round your answe
zvonat [6]

Answer:

Area pf the regular pentagon is 193inch^{2} to the nearest whole number

Step-by-step explanation:

In this question, we are tasked with calculating the area of a regular pentagon, given the apothem and the perimeter

Mathematically, the area of a regular pentagon given the apothem and the perimeter can be calculated using the formula below;

Area of regular pentagon = 1/2 × apothem × perimeter

From the question, we can identify that the value of the apothem is 7.3 inches, while the value of the perimeter is 53 inches

We plug these values into the equation above to get;

Area = 1/2 × 7.3× 53 = 386.9/2 = 193.45 which is 193inch^{2} to the nearest whole number

3 0
3 years ago
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Tyler built a doll house for his sister. The lateral edge of the roof is 13 inches and the dimensions of the base of the house i
melamori03 [73]
I think it is 5616 I times 13 18 24
5 0
3 years ago
Assume that a simple random sample has been selected from a normally distributed population. Find the test statistic t.
lawyer [7]

Using the t-distribution, it is found that the p-value of the test is 0.007.

At the null hypothesis, it is <u>tested if the mean lifetime is not greater than 220,000 miles</u>, that is:

H_0: \mu \leq 220000

At the alternative hypothesis, it is <u>tested if the mean lifetime is greater than 220,000 miles</u>, that is:

H_1: \mu > 220000.

We have the <u>standard deviation for the sample</u>, thus, the t-distribution is used. The test statistic is given by:

t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}

The parameters are:

  • \overline{x} is the sample mean.
  • \mu is the value tested at the null hypothesis.
  • s is the standard deviation of the sample.
  • n is the sample size.

For this problem:

\overline{x} = 226450, \mu = 220000, s = 11500, n = 23

Then, the value of the test statistic is:

t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}

t = \frac{226450 - 220000}{\frac{11500}{\sqrt{23}}}

t = 2.69

We have a right-tailed test(test if the mean is greater than a value), with <u>t = 2.69</u> and 23 - 1 = <u>22 df.</u>

Using a t-distribution calculator, the p-value of the test is of 0.007.

A similar problem is given at brainly.com/question/13873630

8 0
2 years ago
Can U Guys Please Answer These 3 Questions For Me
Damm [24]

Answer:

Step-by-step explanation:

7-2+(4•7)

5+28

=33

3 0
3 years ago
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PLSS HELP IF YOU TURLY KNOW THISS
yaroslaw [1]

Answer:

x = 11

Step-by-step explanation:

(0.3x - 2.1)/3 = 0.4

0.3x - 2.1 = 0.4 * 3

0.3x - 2.1 = 1.2

0.3x = 1.2 + 2.1

0.3x = 3.3

x = 3.3/0.3

x = 11

6 0
3 years ago
Read 2 more answers
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