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EastWind [94]
3 years ago
15

Water can dissolve other substances. which factoer best contributes to this property of water

Chemistry
1 answer:
Crank3 years ago
5 0

Answer:

Simple, the answer would be water particles are not fixed in place.

Explanation:

They move freely and don't stay in one place.

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In your own words, explain why the Linnaean system has changed over time pls help
sergiy2304 [10]

Classification systems are mental models that we create to make sorting things simpler and more efficient. We make compromises to emphasize certain details and hide others based on their perceived relevance to achieving the outcomes we seek. Even if the original model was nearly perfect, you should expect the inputs provided and outcomes desired to change as time goes by.

In time, we usually find that we have over-simplified by ignoring important details. Mental models such as classification systems should evolve over time. This enables them to more accurately reflect reality and lead to the outcomes we seek.

You can only find the details you seek by observing the right layer of abstraction.

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How fast is an airplane traveling that accelerates at a rate of 20 mph per second for 30 seconds?
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6 0
4 years ago
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Why do scientists study seismographs
o-na [289]

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95. Using the standard enthalpy of formation data in Appendix G, calculate the bond energy of the carbon-sulfur double bond in C
prohojiy [21]

Answer:

+523 kJ.

Explanation:

The following data will be used to calculate the average C-S bond energy in CS2(l).

S(s) ---> S(g)

ΔH = 223 kJ/mol

C(s) ---> C(g)

ΔH = 715 kJ/mol

Enthalpy of formation of CS2(l)

ΔH = 88 kJ/mol

CS2(l) ---> CS2(g)

ΔH = 27 kJ/mol

CS2(g) --> C(g) + 2S(g)

So we must construct it stepwise.

1: C(s) ---> C(g) ΔH = 715 kJ

2: 2S(s) ---> 2S(g) ΔH = 446 kJ

adding 1 + 2 = 3

ΔH = 715 + 446

= 1161 kJ

3: C(s) + 2S(s) --> C(g) + 2S(g) ΔH = 1161 kJ

4: C(s) + 2S(s) --> CS2(l) ΔH = 88 kJ

adding (reversed 3) from 4 = 5

ΔH = -1161 + 88

= -1073 kJ

5: C(g) + 2S(g) --> CS2(l) ΔH = -1073 kJ

6: CS2(l) ---> CS2(g) ΔH = 27 kJ

adding 5 + 6 = 7

ΔH = -1073 + 27

= -1046 kJ

7. C(g) + 2S(g) --> CS2(g) ΔH = -1046 kJ

Reverse and divide by 2 for C-S bond enthalpy

= -(-1046)/2

= +523 kJ.

8 0
3 years ago
ASAP HELP WILL MARK BRAINLIEST FOR BEST ANSWER. MUST ANSWER WITHIN 6 MIN!!!
Vesnalui [34]

Answer:

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