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Sladkaya [172]
3 years ago
5

Which statement is true of a reversible reaction at equilibrium?

Chemistry
2 answers:
Arlecino [84]3 years ago
8 0
I believe the answer is D
Vedmedyk [2.9K]3 years ago
7 0

Answer:

D.

The concentration of reactants and the concentration of products are constant.

Explanation:

pls mark as brainliest

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Counting atoms pls someone help me
MrRissso [65]
2 atoms of Al
3 of S
4*3=12 of O
so total= 17
7 0
3 years ago
Which list of elements is arranged in order of increasing electronegativity?
muminat
K, ca, sc is the right answer. Take a look at table S of your chemistry reference table. 
6 0
3 years ago
Read 2 more answers
Which of the following is most likely to make scientific knowledge stronger?
Mariulka [41]

Answer:

D) Evaluating it with experimentation and argument.

Explanation:

If you don't have enough observational evidence, then you can't really strengthen your scientific knowledge, because you haven't collected enough information to answer the questions you're asking.

If you only have a few scientists working on a question, it will take longer to find an answer. With more people working on a concept, it can be solved in more time.

It can be good to create new hypotheses, but only if you've already tested your original hypothesis (with experimentation and argument), and it turned out to be wrong. Once you've rejected your first hypothesis, only then should you make a new one.

8 0
3 years ago
In NMR if a chemical shift(δ) is 211.5 ppm from the tetramethylsilane (TMS) standard and the spectrometer frequency is 556 MHz,
Vika [28.1K]

Answer:

The answer is: 11759 Hz

Explanation:

Given: Chemical shift: δ = 211.5 ppm, Spectrometer frequency = 556 MHz = 556 × 10⁶ Hz

In NMR spectroscopy, the chemical shift (δ), expressed in ppm, of a given nucleus is given by the equation:

\delta (ppm) = \frac{Observed\,frequency (Hz)}{Frequency\,\, of\,\,the\,Spectrometer (MHz)} \times 10^{6}

\therefore Observed\,frequency (Hz)= \frac{\delta (ppm)\times Frequency\,\, of\,\,the\,Spectrometer (MHz)}{10^{6}}

Observed\,frequency= \frac{211.5 ppm \times 556 \times 10^{6} Hz}{10^{6}} = 11759 Hz

<u>Therefore, the signal is at 11759 Hz from the TMS.</u>

6 0
4 years ago
How many ml of 0.112 M Pb(NO3)2 are needed to completely react with 10.0ml of a 0.105 M KI Given Pb(NO3)2 (aq) + 2KI(aq)=2KNO3(a
Brums [2.3K]
0.105 x 10 /2 / 0.112= 4.6875 ml of 0.112M Pb(NO3)2
5 0
3 years ago
Read 2 more answers
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