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Lynna [10]
3 years ago
6

Write a sentence or short paragraph that defines and explains an adaptation

Physics
1 answer:
alexdok [17]3 years ago
3 0
Adaptation is when a living thing changes its behavior to survive in its surroundings.
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Does plants have prokaryotic cells?
vova2212 [387]
No they have eukaryotic cells
7 0
3 years ago
Read 2 more answers
A motorcyclist travels with an average speed of 6 m/s . If the cyclist is going to a friend's house 36 m away , how much time wi
vodka [1.7K]

Answer:

<h2>6 s</h2>

Explanation:

The time taken by the cyclist can be found by using the formula

t  = \frac{d}{v}  \\

v is the velocity

d is the distance

From the question we have

t =  \frac{36}{6}  \\  = 6

We have the final answer as

<h3>6 s</h3>

Hope this helps you

5 0
3 years ago
A vector A⃗ has a length of 8.6 m and points in the negative x direction. Find the x component of the vector −3.7A⃗ .
77julia77 [94]

Answer:

31.8 m in the positive x-direction

Explanation:

Here we have an example of multiplication of a vector by a scalar.

In order to perform this operation, we have to:

- multiply the magnitude of the vector by the scalar

- reverse the direction of the vector if the scalar is a negative number

In this problem, the original vector has a lenght of 8.6 m and it points in the negative x direction. Now we have to find the vector -3.7A, so we have:

- The magnitude is obtained by calculating the product

(3.7)\cdot (8.6)=31.8 m

- The direction is reversed, because the scalar is -3.7, so the new vector will point in the positive x-direction

So the final vector is 31.8 m in the positive x-direction, and therefore its x-component is also 31.8 m in the positive direction.

7 0
3 years ago
An object is placed a distance of twice the focal length away from a diverging lens. What is the magnification of the image?
Bas_tet [7]

Answer:

1/3

Explanation:

We can solve the problem by using the lens equation:

\frac{1}{f}=\frac{1}{p}+\frac{1}{q}

where

f is the focal length

p is the distance of the object from the lens

q is the distance of the image from the lens

Here we have a divering lens, so the focal length must be taken as negative (-f). Moreover, we know that the object is placed at a distance of twice the focal length, so

p=2f

So we can find q from the equation:

\frac{1}{q}=\frac{1}{(-f)}-\frac{1}{p}=-\frac{1}{f}-\frac{1}{2f}=-\frac{3}{2f}\\q=-\frac{2}{3}f

Now we can find the magnification of the image, given by:

M=-\frac{q}{p}=-\frac{-\frac{2}{3}f}{2f}=\frac{1}{3}

8 0
4 years ago
High pitched sounds have relatively large ___ and small ___
Mashutka [201]
High Pitch sounds have relativity large frequency and small wavelength
8 0
4 years ago
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