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3 years ago

What did the romans build as a step toward environment management

1 answer:

6 0

Managing and looking after a port environment. They were also vegetarian. Smoke led to pollution, so there were laws passed that factories could not be built where other buildings could be affected. There were also water systems and sewage systems that carried water to people and carried sewage away from people who could afford it at the time.

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Which component is used to change alternating current to direct current? a diode an integrated circuit a transistor a capacitor

lesantik [10]

As we know that equivalent resistance of a capacitor for an AC circuit is given as

$X_c = \frac{1}{\omega C}$

so here for an AC circuit capacitor will provide less resistance to AC component of the current

While for DC as we know it has ZERO frequency

so we will have large resistance

so here we will have to use capacitor as a filter circuit which will separate AC component of current from the DC current

So correct answer will be

CAPACITOR

4 0

3 years ago

Read 2 more answers

If two bodies weighing 10 kg and 20 kg respectively are standing at the

kvv77 [185]

Answer:

potential energy = mgh , where m is mass of body , g is acceleration due to gravity and h is given height

since both of the body are at same height above the ground , so the body having greater mass will have more potential energy

that is 20 kg body will have higher P.E

Explanation:

7 0

4 years ago

The drawing shows three particles far away from any other objects and located on a straight line. The masses of these particles

miss Akunina [59]

Formula of the gravitational force between two particles:

$F=G\frac{m_1 m_2}{r^2}$

where

$G=6.67 \cdot 10^{-11} Nm^2 kg^{-2}$ is the gravitational constant

m1 and m2 are the masses of the two particles

r is their distance

(a) particle A

The gravitational force exerted by particle B on particle A is

$F_B=G\frac{m_A m_B}{r^2}=(6.67 \cdot 10^{-11}) \frac{(340 kg)(567 kg)}{(0.500 m)^2}=5.14 \cdot 10^{-5} N$ to the right

The gravitational force exerted by particle C on particle A is

$F_C=G\frac{m_A m_C}{r^2}=(6.67 \cdot 10^{-11}) \frac{(340 kg)(139 kg)}{(0.500 m+0.250m)^2}=5.6 \cdot 10^{-6} N$ to the right

So the net gravitational force on particle A is

$F_A = F_B + F_C =5.14 \cdot 10^{-5} N+5.6 \cdot 10^{-6} N=5.7 \cdot 10^{-5} N$ to the right

(b) Particle B

The gravitational force exerted by particle A on particle B is

$F_A=G\frac{m_A m_B}{r^2}=(6.67 \cdot 10^{-11}) \frac{(340 kg)(567 kg)}{(0.500 m)^2}=-5.14 \cdot 10^{-5} N$ to the left

The gravitational force exerted by particle C on particle B is

$F_C=G\frac{m_B m_C}{r^2}=(6.67 \cdot 10^{-11}) \frac{(567 kg)(139 kg)}{(0.250 m)^2}=8.41 \cdot 10^{-5} N$ to the right

So the net gravitational force on particle B is

$F_B = F_A + F_C =-5.14 \cdot 10^{-5} N+8.41 \cdot 10^{-5} N=3.27 \cdot 10^{-5} N$ to the right

The gravitational force exerted by particle A on particle C is

$F_A=G\frac{m_A m_C}{r^2}=(6.67 \cdot 10^{-11}) \frac{(340 kg)(139 kg)}{(0.500 m+0.250m)^2}=-5.6 \cdot 10^{-6} N$ to the left

The gravitational force exerted by particle B on particle C is

$F_B=G\frac{m_B m_C}{r^2}=(6.67 \cdot 10^{-11}) \frac{(567 kg)(139 kg)}{(0.250 m)^2}=-8.41 \cdot 10^{-5} N$ to the left

So the net gravitational force on particle C is

$F_C = F_B + F_A =-8.41 \cdot 10^{-5} N-5.6 \cdot 10^{-6} N=-8.97 \cdot 10^{-5} N$ to the left

3 0

3 years ago

calculate the displacement and velocity of a ball 0.50 seconds after it is thrown straight up with an initial velocity of 15.0 m

iren [92.7K]

Answer:

The ball will have a displacement of 0.5*15.0=7.5m after 0.5 seconds. The velocity of the ball will be 15.0 m/s, since it is not acted on by any forces except gravity (which acts in the direction opposite of the velocity).

Explanation:

We know this is the answer because, according to the kinematic equation:

v^2=u^2+2*a*d

0=15.0^2+2*(-9.8)*d

d=-7.5m

3 0

2 years ago

A class 9 student booked his ticket to moon. His travel company

jasenka [17]

Answer: LET'S TAKE GRAVITY ON EARTH AS 10 N/KG AND ON MOON AS 0.6 N/KG

a) weight=15kgx10N/kg

= 150N

b) weight=15x0.6=9N

c) mass=is the same so 15kg

d) mass is measured in kg, weight in NEWTONS OR $KG M/S^{2}$

e) when the gravitational force is zero

Explanation:

7 0

3 years ago