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3 years ago

10

How do i solve 4(1-x)+3<-2(x+1)

1 answer:

miv72 [106K]3 years ago

8 0

I have no graph , sorry

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Find (f/g) (x) and state the domain restriction. f (x) = 6x - 3 and g(x) = 12x^2 - 6x

Rufina [12.5K]

9514 1404 393

Answer:

(f/g)(x) = 1/(2x)

x ≠ 1/2

Step-by-step explanation:

$(f/g)(x)=\dfrac{f(x)}{g(x)}=\dfrac{6x-3}{12x^2-6x}=\dfrac{6x-3}{2x(6x-3)}\\\\\boxed{(f/g)(x)=\dfrac{1}{2x}}\quad x\ne\dfrac{1}{2}$

The domain restriction x ≠ 1/2 comes from the requirement to prevent the denominator factor 6x-3 from being zero.

8 0

2 years ago

A Air Freshener Used 3 3/4 milliliters perfume wanted to make 3 air freshners how many milliliters of perfume woud she use

larisa [96]

1 and a fourth because 3 3/4 devided by three equals 1 1/4

5 0

3 years ago

It takes 1 yard 2 feet of material to make a pillow. How much material is required to make 8 pillows?

Monica [59]

40 feet or 13 yards and 1 foot

using the conversion

1 yard = 3 feet then 1 yard 2 feet = 5 feet ← material for 1 pillow, hence

8 pillows require 8 × 5 = 40 feet

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2 years ago

8 hr= how many min???<br> Please help fast!

aleksklad [387]

The answer is 8h=480min

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2 years ago

Read 2 more answers

Calculate two iterations of Newton's Method for the function using the given initial guess. (Round your answers to four decimal

pickupchik [31]

Answer:

The first and second iteration of Newton's Method are 3 and $\frac{11}{6}$ .

Step-by-step explanation:

The Newton's Method is a multi-step numerical method for continuous diffentiable function of the form $f(x) = 0$ based on the following formula:

$x_{i+1} = x_{i} -\frac{f(x_{i})}{f'(x_{i})}$

Where:

$x_{i}$ - i-th Approximation, dimensionless.

$x_{i+1}$ - (i+1)-th Approximation, dimensionless.

$f(x_{i})$ - Function evaluated at i-th Approximation, dimensionless.

$f'(x_{i})$ - First derivative evaluated at (i+1)-th Approximation, dimensionless.

Let be $f(x) = x^{2}-8$ and $f'(x) = 2\cdot x$ , the resultant expression is:

$x_{i+1} = x_{i} -\frac{x_{i}^{2}-8}{2\cdot x_{i}}$

First iteration: ( $x_{1} = 2$ )

$x_{2} = 2-\frac{2^{2}-8}{2\cdot (2)}$

$x_{2} = 2 + \frac{4}{4}$

$x_{2} = 3$

Second iteration: ( $x_{2} = 3$ )

$x_{3} = 3-\frac{3^{2}-8}{2\cdot (3)}$

$x_{3} = 2 - \frac{1}{6}$

$x_{3} = \frac{11}{6}$

7 0

3 years ago