Is it possible to draw a triangle whose angles measure 50°, 50°, and 80°?

1 answer:

5 0

First of all, we know a quality of all interior angles of a triangle, they should add to 180 degrees.

Does 50+50+80 degrees give 180 degrees?

100+80=180 degrees

Therefore, yes, it is possible to draw a triangle with the angle measures given to be 50, 50 and 80 degrees.

Hope I helped :)

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The population of a town increased from 3650 in 2012 to 4700 in 2014. Find the absolute increase.

aev [14]

Treat this like a slope formula. Y2-y1 divided by x2-x1.
Your y2 value is the second population
Y1= value of first population.
X2= second year they give
X1= first year they give.
4700-3650
_________
2014-2012

1050
____
2

525 is the increase a year

8 0

3 years ago

Plz help me with this

AnnZ [28]

Answer: $\bold{A)\quad y=5sin\bigg(\dfrac{6}{5}x-\pi\bigg)-4}$

<u>Step-by-step explanation:</u>

The general form of a sin/cos function is: y = A sin/cos (Bx-C) + D where the period (P) = 2π ÷ B

In the given function, $B=\dfrac{6}{5}$ → $P=2\pi \cdot \dfrac{5}{6}=\dfrac{10\pi}{3}$

Half of that period is: $\dfrac{1}{2}\cdot \dfrac{10\pi}{3}=\large\boxed{\dfrac{5\pi}{3}}$

Calculate the period for each of the options to find a match:

$A)\quad B=\dfrac{6}{5}:\quad 2\pi \div \dfrac{6}{5}=2\pi \cdot \dfrac{5}{6}=\dfrac{5\pi}{3}\quad \leftarrow\text{THIS WORKS!}\\\\\\B)\quad B=\dfrac{6}{10}:\quad 2\pi \div \dfrac{6}{10}=2\pi \cdot \dfrac{10}{6}=\dfrac{10\pi}{3}\\\\\\C)\quad B=\dfrac{5}{6}:\quad 2\pi \div \dfrac{5}{6}=2\pi \cdot \dfrac{6}{5}=\dfrac{12\pi}{5}\\\\\\D)\quad B=\dfrac{3}{10}:\quad 2\pi \div \dfrac{3}{10}=2\pi \cdot \dfrac{10}{3}=\dfrac{20\pi}{3}$