Answer:
This question is from a case study which i went through to find the answer of the question. In the case study Albert suffered from a stroke in which his left side of the brain was affected. However, the symptoms were present in the right side of the body.
This actually happens when a person experiences stroke his symptoms are present only in single side of the body because of the rupture of the blood vessels in specific side.
As we know that when descending nerve tracts intersect each other, the right side of the body is controlled by left side of the brain and left side of the body is controlled by the right side of the brain.
Therefore, when the symptoms of Albert were localized in only right side, it was concluded that Albert had suffered the damage in right side of the brain.
Hope it helps!
Answer:
Molecules which move against the concentration gradient across the cell membrane employ the mechanism of active transportation.
Explanation:
Normally, permitted molecules moves across the cell membrane of the cell by the process of diffusion and osmosis. This is used when molecules move from hypertonic region to hypotonic region (if ions) and hypotonic to hypertonic (if water). This is a passive transportation which do not require the expense of energy from the cell.
In contrast, when molecules move in or out of the cell against their concentration gradient, that is ions moving from hypotonic region to hypertonic region, they implore the expense of energy in form of adenosine triphosphate (ATP), and the involvement of the membrane carrier proteins. This is called active transport.
Answer:
Ss × ss
Explanation:
This question involves a single gene coding for hair length in guinea pigs. The alleles for short hair (S) is dominant over that of long hair (s).
According to this question, a guinea pig with short hair (S_) is crossed to one that has long hair (ss) to produce offsprings that have 44 short hair and 46 long hair. This number of offsprings produced indicate a ratio of 1:1, which can only be produced if the short haired guinea pig is heterozygous i.e. Ss.
Therefore, the genotype of the parents are Ss (short hair) and ss (long hair) i.e. Ss × ss. This combination will produce offsprings with the following proportion: Ss (1) : ss (1).
Type O is the remainder after subtracting types A, B and AB.
so percentage of type O blood supply
= 100%-(28+15+10)%
= 100% - 53%
= 47%
Cells because they are living things. Hope this helps! ;D
