Question

An apparatus like the one Cavendish used to find G has large lead balls that are 8.4 kg in mass and small ones that are 0.061 kg. The center of a large ball is separated by 0.057 m from the center of a small ball. Find the magnitude of the gravitational force between the masses if the value of the universal gravitational constant is 6.67259 × 10−11 Nm2/kg2

Answer 1

Answer:

The gravitational force is $1.05\times10^{-8}\ N$

Explanation:

Given that,

Mass of large ball = 8.4 kg

Mass of small ball = 0.061 kg

Separation = 0.057 m

Gravitational constant $G= 6.67\times10^{-11}\ Nm^2/kg^2$

We need to calculate the gravitational force

Using formula of gravitational force

$F= \dfrac{Gm_{1}m_{2}}{r^2}$

Put the value into the formula

$F=\dfrac{6.67259\times10^{-11}\times8.4\times0.061}{(0.057)^2}$

$F=1.05\times10^{-8}\ N$

Hence,  The gravitational force is $1.05\times10^{-8}\ N$