Answer:
B = 8.0487mT
Explanation:
To solve the exercise it is necessary to take into account the considerations of the Magnetic Force described by Faraday,
The magnetic force is given by the formula
Where,
B = Magnetic Field
I = Current
L = Length
Angle between the magnetic field and the velocity, for this case are perpendicular, then is 90 degrees
According to our data we have that
I = 16.4A
F = 0.132N/m
As we know our equation must be modificated to Force per length unit, that is
Replacing the values we have that
Solving for B,
It’s A because energy passes freely through the atmosphere and is absorbed by earths surface.
Answer:
v = √ 2e (V₂-V₁) / m
Explanation:
For this exercise we can use the conservation of the energy of the electron
At the highest point. Resting on the top plate
Em₀ = U = -e V₁
At the lowest point. Just before touching the bottom plate
Emf = K + U = ½ m v² - e V₂
Energy is conserved
Em₀ = Emf
-eV₁ = ½ m v² - e V₂
v = √ 2e (V₂-V₁) / m
Where e is the charge of the electron, V₂-V₁ is the potential difference applied to the capacitor and m is the mass of the electron
Answer:
241.24m
Explanation:
The height at which the shell explodes will be at the maximum height. In projectile motion, maximum height formula is expressed as:
H = u²sin²θ/2g
u is the initial speed = 70m/s
θ the angle of launch = 75°
g is the acceleration due to gravity = 9.81m/s²
Substitute the values into the formula and get H
H = 70²(sin75°)/2(9.81)
H = 4900sin75°/19.62
H = 4900*0.9659/19.62
H = 4733.037/19.62
H = 241.24m
Hence the height at which the shell explodes is 241.24m
