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Lerok [7]
2 years ago
14

Physics laws of motion

Physics
1 answer:
expeople1 [14]2 years ago
8 0

The acceleration is 0.095 m/s^2

Explanation:

We can solve the problem by applying Newton's second law of motion: in fact, the net force acting on an object is equal to the product between the mass of the object and its acceleration. Therefore we can write:

\sum F = ma

where:

\sum F is the resultant force acting on the object

m is its mass

a is its acceleration

In this problem, we have the following forces acting on the system:

F_1 = 2500 N (forward)

F_2 = -2400 N (backward)

So, Newton's second law can be rewritten as:

F_1 -F_2 = ma

where:

m = 1050 kg is the mass of all the students

Solving the formula for a, we find the acceleration of the system:

a=\frac{F_1-F_2}{m}=\frac{2500+(-2400)}{1050}=0.095 m/s^2

Learn more about Newton's second law:

brainly.com/question/3820012

#LearnwithBrainly

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What travels by vibrating particles? Mechincal Waves or ElecrtoMagnetic Waves.
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Explanation:

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if a gas has a gage pressure of 156 kpa its absolute pressure is approximately .....A... 56 kPa ....B....100 kPa.......C......25
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256 kPa because p-guage + p-absolute + p-atmospheric = 256

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3 years ago
A transform boundary occurs where two tectonic plates _____.?
gladu [14]

Where they slide over each other.

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Read 2 more answers
when a metal ball is heated through 30°c,it volume becomes 1.0018cm^3 if the linear expansivity of the material of the ball is 2
Vlad1618 [11]

Answer:

The original volume of the metal sphere is approximately 1 cm³

Explanation:

The given parameters are;

The temperature change of the metal ball, ΔT = 30°C = 30 K

The new volume of the metal ball, V₂  = 1.0018 cm³

The linear expansivity of the material ball, α = 2.0 × 10⁻⁵ K⁻¹

We have;

d₂ = d₁·(1 + α·ΔT)

Where;

d₁ = The original diameter of the metal ball

d₂ = The new diameter of the ball

From the volume of the ball, V₂, we have;

V₂ = 1.0018 cm³ = (4/3)×π×r₂³

Where;

r₂ = The new radius = d₂/2

∴ V₂ = 1.0018 cm³ = (4/3)×π×(d₂/2)³

∴ d₂ = ∛(2³ × 1.0018 cm³/((4/3) × π)) ≈ 1.241445 cm

d₁ = d₂/(1 + α·ΔT)

∴ d₁ ≈ 1.241445 cm/(1 + 2.0 × 10⁻⁵·K × 30 K) ≈ 1.24070058 cm

The original volume of the metal ball, V₁ = (4/3)×π×(d₁/2)³

∴ V₁ = (4/3)×π×(1.24070058/2)³ ≈ 0.99999902845 cm³ ≈ 1 cm³

The original volume of the metal sphere, V₁ ≈ 1 cm³.

8 0
2 years ago
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