-- loud sounds
-- bright lights
-- strong radio signals
-- Slinkies that can pinch you painfully
-- a tsunami in the ocean
-- earthquakes above Richter 5 or 6
Answer:
v0x = 104.89 m/s
The vector v0x will be:
v0x = (104.89 m/s, 0)
Explanation:
Please, see the attached figure for a better understanding of the problem.
To obtain v0x, we have to use this trigonometric rule:
cos θ = adjacent / hypotenuse
Seeing the figure, notice that the side adjacent to the angle θ is the x-component of the initial velocity v0. The hypotenuse is the magnitude of the vector v0. Then:
cos θ = magnitude v0x / magnitude v0
magnitude v0 * cos θ = magnitude v0x
151.0 m/s * cos 46 = magnitude v0x
magnitude v0x = 104.89 m/s
The vector v0x will be:
v0x = (104.89 m/s, 0)
In order to solve the problem it is necessary to take into account the concepts related to the moment of inertia, and the center of mass of the object.
Our values are given by:
m = 0.514kg
I = 4.7m (each side)
A) For the case when the axis passes through the midpoints of opposite sidesand lies in the plane of the square. The formula is given by,
B) For the case when the axis passes through the midpoint of one of the sides and is perpendicular to the plane of the square. The formula is given by,
C) For the case when the axis lies in the plane of square f passes through two diagonally opposite particles,
The large can of solids will reach before the empty can reason being is it has more additional weight its like dropping a 1 pound weight compared to a 4 pound the 4 pound reaches faster because of the gravitational pull the size of the pull depends on the masses of the objects