The weight of a 100 N laser printer is spread over 0.5m2. What is the pressure it exerts?
2 answers:
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Given:
F = 39 N, the force applied
t = 2 s, the time interval in which the force is applied.
By definition, the impulse is
Answer: 78 N-s
F = 39 N, the force applied
t = 2 s, the time interval in which the force is applied.
By definition, the impulse is
Answer: 78 N-s
Answer:
f = 614.28 Hz
Explanation:
Given that, the length of the air column in the test tube is 14.0 cm. It can be assumed that the speed of sound in air is 344 m/s. The test tube is a kind of tube which has a closed end. The frequency in of standing wave in a closed end tube is given by :
f = 614.28 Hz
So, the frequency of the this standing wave is 614.28 Hz. Hence, this is the required solution.