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3 years ago

NO LINKS! ASAP PLEASE FOR TEST TOMORROW

Physics

1 answer:

denis23 [38]3 years ago

8 0

Answer:

Friction: When two surfaces slide against each other / make contact with each other

Force: A push or pull exerted on an object

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Determine an appropriate size for a square cross-section solid steel shaft to transmit 260 hp at a speed of 550 rev/min if the m

Phantasy [73]

Answer:46.05 mm

Explanation:

Given

$Power=260\ hp\approx 260\times 746=193.96\ KW$

speed $N=550\ rev/min$

allowable shear stress $(\tau )_{max}=15\ kpsi\approx 103.421\ MPa$

Power is given by

$P=\frac{2\pi NT}{60}$

$193.96=\frac{2\pi 550\times T}{60}$

$T=3367.6\ N-m$

From Torsion Formula

$\frac{T}{J}=\frac{\tau }{r}-----1$

where J=Polar section modulus

T=Torque

$\tau$ =shear stress

For square cross section

$r=\frac{a}{2}$

where a=side of square

$J=\frac{a^4}{6}$

Substituting the values in equation 1

$\frac{3376.6}{\frac{a^4}{6}}=\frac{103.421\times 10^6}{\frac{a}{2}}$

$a=0.04605\ m$

$a=46.05\ mm$

7 0

3 years ago

A man stands at the edge of a cliff and throws a rock downward with A speed of 12.0 m s . Sometimes later it strikes the ground

kvasek [131]

B) 48.0 m/s

We can actually start to solve the problem from B for simplicity.

The motion of the rock is a uniformly accelerated motion (free fall), so we can find the final speed using the following suvat equation

$v^2 -u^2 = 2as$

where

$v$ is the final velocity

$u = 12.0$ is the initial velocity (positive since we take downward as positive direction)

$a=g=9.8 m/s^2$ is the acceleration of gravity

s = 110 m is the vertical displacement

Solving for v, we find the final velocity (and so, the speed of the rock at impact):

$v = \sqrt{u^2+2as}=\sqrt{12^2+2(9.8)(110)}=48.0 m/s$

A) 3.67 s

Now we can find the time of flight of the rock by using the following suvat equation

$v=u+at$

where

$v = 48.0$ is the final velocity at the moment of impact

$u = 12.0$ is the initial velocity

$a=g=9.8 m/s^2$ is the acceleration of gravity

t is the time it takes for the rock to reach the ground

And solving for t, we find

$t=\frac{v-u}{a}=\frac{48.0-12.0}{9.8}=3.67 s$

6 0

3 years ago

What characteristics determine how easily two substances change temperature

marissa [1.9K]

Amount of time the two substances are in contact. area in contact between the two substances. amount of heat needed to raise the temperature one degree Celsiusof the material that makes up the substances. density of the two substances in contact.J

4 0

3 years ago

PLEASE HELP ASAP!!!!!!!!!!!!

lianna [129]

The first choice on the list is the correct one.

7 0

4 years ago

A block weighing 9.3 N requires a force of 3.7 N to push it along at constant velocity. What is the coefficient of friction for

olga_2 [115]

Answer:

0.398

Explanation:

According to friction, the frictional force is directly proportional to the normal reaction

Ff = nR

Ff is the frictional force

n is the coefficient of friction

R is the reaction

Reaction is equal to the weight

R= W = 9.3N

Fm = Ff = 3.7N

Fm is the moving force

Get the coefficient of friction

n = Ff/R

n = 3.7/9.3

n = 0.398

Hence the coefficient of friction for the surface is 0.398

3 0

3 years ago

NO LINKS! ASAP PLEASE *FOR TEST TOMORROW*

NO LINKS! ASAP PLEASE FOR TEST TOMORROW