Answer:
The correct solution is " %".
Explanation:
The given values are:
Pressure,
for copper,
As we know,
The Bulk Modulus (B) =
or,
The decrease in volume will be:
=
then,
=
On putting the values, we get
=
=
Answer:
Explanation:
L 1: front radius 950 mm, rear radius 2700 mm, refractive index 1.528;
We shall use lens maker's formula , that is
1/f = (μ-1) ( 1/R₁ - 1/R₂) , μ is refractive index of the lens , R₁ and R₂ are radius of curvature of front and rear curved surface.
1/f₁ = (1.528-1)( 1/950 + 1/2700)
f₁ = 1331 mm
L2: front radius 535 mm, rear radius 500 mm, refractive index 1.550.
1/f₂ = (1.550-1)( 1/535 + 1/500)
f₂ = 470 mm
largest angular magnification possible
= f₁ /f₂
= 1331 / 470
= 2.83 ( approx )
Length between two lenses
=1331 +470
= 1801 mm
= 1.8 m Ans
It can be done by you only as we can't access those data in documents.
Let me show steps
- Read the introduction first.
- See below there are two documents in blue
- Lab report guide
- Lab report public
- Use first one in order to prepare the lap report guide
- Use second one in order to public them .
- Submit all files at add file option.
Answer:
The answer is 62 (B)
Explanation:
Just took the pre-test
"Points earned on this question: 1"