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Nikitich [7]
3 years ago
9

A volleyball player’s hand applies a 39 N force while in contact with a volleyball for 2 seconds. What is the impulse on the bal

l?
Physics
2 answers:
Anna11 [10]3 years ago
5 0

Answer:

78 N - S

Explanation:

It is correct

nikklg [1K]3 years ago
3 0
Given:
F = 39 N, the force applied
t = 2 s, the time interval in which the force is applied.

By definition, the impulse is
I = \int_{0}^{2} F(t) dt = \int _{0}^{2} 39dt = 39*2=78 \, N-s

Answer: 78 N-s
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3 years ago
A car travels at a constant speed around a circular track whose radiu is 2.6 km. The goes once arond the track in 360s . What is
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Answer:

Centripetal acceleration = 0.79 m/s²

Explanation:

<u>Given the following data;</u>

Radius, r = 2.6 km

Time = 360 seconds

<em><u>Conversion:</u></em>

2.6 km to meters = 2.6 * 1000 = 2600 meters

To find the magnitude of centripetal acceleration;

First of all, we would determine the circular speed of the car using the formula;

Circular \; speed (V) = \frac {2 \pi r}{t}

Where;

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Substituting into the formula, we have;

Circular \; speed (V) = \frac {2*3.142*2600}{360}

Circular \; speed (V) = \frac {16338.4}{360}

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Next, we find the centripetal acceleration;

Mathematically, centripetal acceleration is given by the formula;

Centripetal \; acceleration = \frac {V^{2}}{r}

Where;

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Substituting into the formula, we have;

Centripetal \; acceleration = \frac {45.38^{2}}{2.6}

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3 years ago
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h=ut+\dfrac{1}{2}at^2

Here, u = 0 and a = g

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