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yKpoI14uk [10]
4 years ago
9

Suppose that Max and Maria recorded data from

Chemistry
2 answers:
Lemur [1.5K]4 years ago
4 0

D

extra words for 20 letters

Anna007 [38]4 years ago
3 0

Answer:

He used too few significant digits

Explanation:

The answer is D

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12. How is the melting point of a substance related to its freezing point? Both indicate the temperature at which the solid and
krok68 [10]
Both indicate the temperature at which the solid and liquid states of a substance are in equilibrium would be your answer.

This is beacause the melting point of a substance is the same as the freezing point of a substance. At this particular temp, the substance can be either a solid or a liquid. 

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How does e=mc^2 connect to quarks
Jobisdone [24]

Answer:

good bro

Explanation:

5 0
3 years ago
(01.01 LC)
Usimov [2.4K]

The answer would be "false" or the second option. A opinion is what you think on a certain subject and science is full of facts and opinions of other scientist which would mean your using someone else for your opinion just remember opinions is what you think about a subject and you can't use science for your opinion.

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4 years ago
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(4) Calculate the % of a compound that can be removed from liquid phase 1 by using ONE to FOUR extractions with a liquid phase 2
maksim [4K]

Answer:

One extraction: 50%

Two extractions: 75%

Three extractions: 87.5%

Four extractions: 93.75%

Explanation:

The following equation relates the fraction q of the compound left in volume V₁ of phase 1 that is extracted n times with volume V₂.

qⁿ = (V₁/(V₁ + KV₂))ⁿ

We also know that V₂ = 1/2(V₁) and K = 2, so these expressions can be substituted into the above equation:

qⁿ = (V₁/(V₁ + 2(1/2V₁))ⁿ = (V₁/(V₁ + V₁))ⁿ =  (V₁/(2V₁))ⁿ = (1/2)ⁿ

When n = 1, q = 1/2, so the fraction removed from phase 1 is also 1/2, or 50%.

When n = 2, q = (1/2)² = 1/4, so the fraction removed from phase 1 is (1 - 1/4) = 3/4 or 75%.

When n = 3, q = (1/2)³ = 1/8, so the fraction removed from phase 1 is (1 - 1/8) = 7/8 or 87.5%.

When n = 4, q = (1/2)⁴ = 1/16, so the fraction removed from phase 1 is (1 - 1/16) = 15/16 or 93.75%.

5 0
3 years ago
If the mass of a box is 140 g, and the volume is 8 cm3, then the density of the box = ? socratic.org
Ksivusya [100]

Answer:

17.5 g/cm³

Explanation:

We can solve this particular problem by keeping in mind the <em>definition of density</em>:

  • Density = mass / volume

As the problem gives us both <em>the mass and the volume</em> of the box, we can now proceed to <u>calculate the density</u>:

  • Density = 140 g / 8 cm³
  • Density = 17.5 g/cm³

The density of the box is 17.5 g/cm³.

4 0
3 years ago
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