Answer:
Number of moles = 3.82 mol
Explanation:
Given data:
Number of moles of CO₂ = ?
Mass of CO₂ = 168.2 g
Solution:
Number of moles = mass/molar mass
Molar mass of CO₂ = 44 g/mol
By putting values,
Number of moles = 168.2 g/ 44 g/mol
Number of moles = 3.82 mol
Answer:
The turnover number is the maximum substrate quantitiy converted to product per enzyme and per second. It can be calculate as follows:
![k_c = \frac{V_{max}}{[E]}](https://tex.z-dn.net/?f=k_c%20%3D%20%5Cfrac%7BV_%7Bmax%7D%7D%7B%5BE%5D%7D)
with ![[E]](https://tex.z-dn.net/?f=%5BE%5D)
active enzyme concentration.
In this case we have Vmax an data to calculate
![[E]=\frac{3.38*10^{-14}}{0.01 L}=3.38*10^{-12} M](https://tex.z-dn.net/?f=%5BE%5D%3D%5Cfrac%7B3.38%2A10%5E%7B-14%7D%7D%7B0.01%20L%7D%3D3.38%2A10%5E%7B-12%7D%20M%20)
Now 
it is not like any option.
If we assume that 
have the non usual units of 
and it is 
So we need divide by the moles of E (in place of [E])
Now 
(pass from 
to 
dividing by 60)
Answer:you should search on google
Explanation:
because its useful
Answer:
9 L
Explanation:
According to the question , the given reaction is -
2NO(g) + O₂(g)------->2NO₂(g)
Since ,
At STP ,
One mole of a gas occupies the volume of 22.4 L.
Hence , as given in the question -
9 L of NO , i.e .
22.4 L = 1 mol
1 L = 1 / 22.4 mol
9 L = 1 / 22.4 * 9 L = 0.40 mol
From the chemical reaction ,
The Oxygen is in excess , hence NO becomes the limiting reagent , and will determine the moles of product .
Hence ,
2 moles of NO will produce 2 moles of NO₂.
Therefore ,
0.40 mol of NO will produce 0.40 mol of NO₂.
Hence , the volume of NO₂ can be calculated as -
1 mol = 22.4 L
0.40 mol = 0.40 * 22.4 L = 9 L
