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iren2701 [21]
3 years ago
13

Which of the following combinations of particles represents an ion of net charge -1 and of mass number 82? Group of answer choic

es:
A) 46 neutrons, 35 protons, 36 electrons
B) 46 neutrons, 36 protons, 35 electrons
C) 46 neutrons, 36 protons, 36 electrons
D) 47 neutrons, 35 protons, 35 electrons
E) 47 neutrons, 35 protons, 36 electrons
Chemistry
1 answer:
noname [10]3 years ago
5 0

Answer:

The correct choice is E (47 neutrons, 35 protons, 36 electrons)

Explanation:

A ion of net charge -1 means that the ion wins an e-.

We dismiss options B and C.

We also dismiss option A because neutrons + protons = 81.

neutrons + protons = mass number

So we have E and C.

We see that C has 47 neutrons, 36 protons and 36 electrons and, as the atomic number matches the number of protons, we find out on the Periodic Table that the atomic number 36 represents to Krypton, a noble gas. It is impossible! A noble gas never can't be a ion of net charge.

Option E is correct, It is an isotope of Br.

Br has 35 protons (its atomic number)

47 neutrons, that's why it is an Isotope (Br has always 45 neutrons)

As usual, Br has 35 electrons, if it represents a ion of net charge -1, it menas it won 1 e-.  

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Calculate the heat needed to be removed to freeze 45g of water at 0C
alexira [117]

Answer: The heat needed to be removed to freeze 45.0 g of water at 0.0 °C is 15.01 KJ.

Explanation:

  • Firstly, we need to define the term <em>"latent heat"</em> which is the amount of energy required "absorbed or removed" to change the phase "physical state; solid, liquid and vapor" without changing the temperature.
  • Types of latent heat: depends on the phases that the change occur between them;
  1. Liquid → vapor, <em>latent heat of vaporization</em> and energy is absorbed.
  2. Vapor → liquid, latent heat of liquification and the energy is removed.
  3. Liquid → solid, <em>latent heat of solidification</em> and the energy is removed.
  4. Solid → liquid, <em>latent heat of fusion</em> and the energy is absorbed.
  • In our problem, we deals with latent heat of freezing "solidification" of water.
  • The latent heat of freezing of water, ΔHf, = 333.55 J/g; which means that the energy required to be removed to convert 1.0 g of water from liquid to solid "freezing" is 333.55 g at 0.0 °C.
  • Then the amount of energy needed to be removed to freeze 45.0 g of water at 0.0 °C is (ΔHf x no. of grams of water) = (333.55 J/g)(45.0 g) = 15009.75 J = 15.01 KJ.

4 0
4 years ago
What is 5.1821 x 10^-4 in standard format
Darya [45]
The answer is 1.39E-7
4 0
4 years ago
The activation energy for the reaction NO2(g)+CO(g)⟶NO(g)+CO2(g) is Ea = 375 kJ/mol and the change in enthalpy for the reaction
HACTEHA [7]
Answer: 625 kj/mol

Explanation:

As shown below this expression gives the activation energy of the reverse reaction:

EA reverse reaction = EA forward reaction + | enthalpy change |

1) The activation energy, EA is the difference between the potential energies of the reactants and the transition state:

EA = energy of the transition state - energy of the reactants.

2) The activation energy of the forward reaction given is:

EA = energy of the transition state - energy of  [ NO2(g) + CO(g) ] = 75 kj/mol

3) The negative enthalpy change - 250 kj / mol for the forward reaction means that the products are below in the potential energy diagram, and that the potential energy of the products, [NO(g) + CO2(g) ] is equal to 375 kj / mol - 250 kj / mol = 125 kj/mol

4) For the reverse reaction the reactants are [NO(g) + CO2(g)], and the transition state is the same than that for the forward reaction.

5) The difference of energy between the transition state and the potential energy of [NO(g) + CO2(g) ] will be the absolute value of the change of enthalpy plus the activation energy for the forward reaction:

EA reverse reaction = EA forward reaction + | enthalpy change |

EA reverse reaction = 375 kj / mol + |-250 kj/mol | = 375 kj/mol + 250 kj/mol = 625 kj/mol.

And that is the answer, 625 kj/mol
4 0
3 years ago
If 125 mL of a 1.1 M glucose solution is diluted to 500.0 mL , what is the molarity of the diluted solution? Express your answer
Juli2301 [7.4K]

Answer:

0.28M

Explanation:

From the question given, we obtained the following information:

C1 = 1.1 M

V1 = 125mL

V2 = 500mL

C2 =?

Using the dilution formula C1V1 = C2V2, we can easily find the molarity of the diluted solution as follows:

C1V1 = C2V2

1.1 x 125 = C2 x 500

Divide both side by 500

C2 = (1.1 x 125)/500 =

C2 = 0.28M

3 0
3 years ago
Hydrocarbons are compounds that are composed of carbon and hydrogen. Which statement does the law of definite proportions suppor
lora16 [44]
The correct option is A.
The law of definite proportion states that a given chemical compound always contains its component elements in fixed ratio irrespective of the source they are obtain from.
For instance, water is made up of two atoms of hydrogen and one atom of oxygen. Water can not be formed in any other way. Combining the oxygen and the hydrogen in another ratio will give us another thing not water.
6 0
4 years ago
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