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Dimas [21]
3 years ago
10

The heat capacity of a bomb calorimeter was determined by burning 6.79 g of methane (energy of combustion = -802 kJ/mol CH4) in

the bomb. The temperature changed by 15.7°C. (a) What is the heat capacity of the bomb?
Chemistry
1 answer:
Ratling [72]3 years ago
7 0

Answer:

The answer to your question is: Cp = 7.52 kJ/g°C

Explanation:

Data

Cp = ?

mass = 6.79 g

Energy = -802 kJ/mol   CH₄

ΔT = 15.7°C

Formula

Q = mCpΔT

Solve for Cp

Cp = \frac{Q}{mΔT}

Process

- Convert energy to J

                                     -802kJ/mol = - 802 000 J/mol

- Calculate heat capacity

                          Cp = \frac{802 000}{(6.79)(15.7)}

                                 Cp = 7523 J/ g°C   or

                                 Cp = 7.52 kJ/g°C

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Answer:

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Let's rewrite the given word equation in its chemical balanced equation representation:

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To plot the calibration curve, you need to prepare iron solutions with known concentrations and measure their absorbance. You need to pipet 0 mL of the diluted solution to have 0.00 mg of iron.

In spectrophotometry, to plot the calibration curve, you need to prepare solutions with known concentrations and measure their absorbance.

We have a standard iron solution with a concentration of 0.2500g/L of pure iron (C₁). We pipet 25.00mL (V₁) of this standard iron solution into a 500mL (V₂) volumetric flask and dilute up to the mark with distilled water.

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Then, if we wanted to prepare the blank, that is, the solution that contains the same matrix but not the analyte, and whose concentration in iron is 0.00 mg/L, we wouldn't pipet any of the diluted solution.

To plot the calibration curve, you need to prepare iron solutions with known concentrations and measure their absorbance. You need to pipet 0 mL of the diluted solution to have 0.00 mg of iron.

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