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aksik [14]
3 years ago
9

A solution contains AgNO3 and Ba(NO3)2. What substance could be added to the solution to precipitate Ag+ ions, but leave Ba2+ io

ns in solution? NaNO3 Na2SO4 NaCl After removal of the Ag+ compound, what could then be added to the solution to precipitate the Ba2+ ions? NaNO3 Na2SO4 NaCl
Chemistry
1 answer:
SOVA2 [1]3 years ago
4 0

Answer:

It uses sodium nitrate, so that the nitrate group reacts with silver and precipitates as a salt, thus forming silver nitrate

And as for the precipitation of barium, I would use sodium sulfate, since we would use the nitrate group, barium nitrate would form, which is very dangerous and is considered high risk.

Explanation:

All the compounds that we name are reactions where as a product they give salts that are highly complex, where they are solid at room temperature, precipitate and are whitish in color.

These salts so that they precipitate it is important that they are in supersaturation since otherwise they will be in constant dynamism dissolving with the water, since they are soluble in them and the decantation will not be perceived at the naked eye of the human eye.

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What volume of a 0. 100mhcl stock solution should be used to prepare 250. 00ml of 0. 0250mhcl?.
Alex_Xolod [135]

62.5 mL is prepare .

What is molarity?

Molar concentration is a unit of measurement for the concentration of a chemical species, specifically a solute, in a solution, expressed as the amount of substance per unit volume of solution. The most often used unit for molarity in chemistry is the number of moles per litre, denoted by the unit symbol mol/L or mol/dm3 in SI units.

Molarity of the stock solution as 0.100 M

Volume of the dilute solution as 250 mL

Molarity of dilute solution as 0.0250 M

We are required to calculate the Volume of the stalk solution.

Taking the volume and molarity of the stock solution to be V₁ and M₁ respectively, and volume and molarity of the dilute solution to be V₂ and M₂ respectively.

We are going to use the dilution formula;

According to the dilution formula, M₁V₁ = M₂V₂

Rearranging the formula;

V₁ = M₂V₂ ÷ M₁

   = (0.025 M × 0.25 L) ÷ 0.100 M

   = 0.0625 L

But, 1 L = 1000 mL

V₁ = 62.5 mL

Therefore, the volume of the stock solution is 62.5 mL

Learn more about molarity from given link

brainly.com/question/26873446

#SPJ4

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All of the following are reasons why equations or balanced EXCEPT
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monkey

Explanation:

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