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Doss [256]
2 years ago
13

How many grams of a 31.6% potassium sulfate solution would contain 617 g potassium sulfate?

Chemistry
1 answer:
dimulka [17.4K]2 years ago
6 0
The answer would be 1952.5 grams of potassium sulfate solution. The way to get the answer is to use the equation, 617/x = 31.6%/1 and then cross multiply to get 31.6%x= 617grams and then 0.316x=617 grams so then x = 617/0.316= 1952.5 grams. 
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Answer: The empirical formula is CH_2.

Explanation:

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Step 1 : convert given masses into moles.

Moles of C = \frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{1.71g}{12g/mole}=0.142moles

Moles of H = \frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{0.287g}{1g/mole}=0.287moles

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The ratio of C: H = 1: 2

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