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3 years ago

What is the poh of a 4.5x10^-3 m oh- solution?

Chemistry

2 answers:

Diano4ka-milaya [45]3 years ago

8 0

<u>Answer:</u> The pOh of the given solution is 2.35

<u>Explanation:</u>

pOH is defined as the negative logarithm of hydroxide ion concentration present in a solution. The equation used to represent pOH of the solution follows:

$pOH=-\log[OH^-]$

We are given:

$[OH^-]=4.5\times 10^{-3}M$

Putting values in above equation, we get:

$pOH=-\log(4.5\times 10^{-3})$

$pOH=2.35$

Hence, pOH of the given solution is 2.35

Ksju [112]3 years ago

6 0

The formula for pOH is -log(M)

So, all we need to do is plug in that number! -log(4.5x10^-3)
That gives us 2.3, so the pOH is 2.3 :)

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