Answer:
Hello! Your answer would be, D) HCI
Explanation:
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The greater the friction, or rubbing, between particles in any fluid, the higher the viscosity. A fluid with a high viscosity has a large amount of internal friction. As the temperature of a gas increases, friction increases, and so the viscosity of the gas increases. The warmer the gas, the slower it flows.
<u>Answer:</u> The net ionic equation is written above
<u>Explanation:</u>
Net ionic equation of any reaction does not include any spectator ions.
Spectator ions are defined as the ions which does not get involved in a chemical equation. They are found on both the sides of the chemical reaction when it is present in ionic form.
The chemical equation for the reaction of lead (II) nitrate and potassium sulfate is given as:
![Pb(NO_3)_2(aq.)+K_2SO_4(aq.)\rightarrow 2KNO_3(aq.)+PbSO_4(s)](https://tex.z-dn.net/?f=Pb%28NO_3%29_2%28aq.%29%2BK_2SO_4%28aq.%29%5Crightarrow%202KNO_3%28aq.%29%2BPbSO_4%28s%29)
Ionic form of the above equation follows:
![Pb^{2+}(aq.)+2NO_3^{-}(aq.)+2K^{+}(aq.)+SO_4^{2-}(aq.)\rightarrow PbSO_4(s)+2K^+(aq.)+2NO_3^-(aq.)](https://tex.z-dn.net/?f=Pb%5E%7B2%2B%7D%28aq.%29%2B2NO_3%5E%7B-%7D%28aq.%29%2B2K%5E%7B%2B%7D%28aq.%29%2BSO_4%5E%7B2-%7D%28aq.%29%5Crightarrow%20PbSO_4%28s%29%2B2K%5E%2B%28aq.%29%2B2NO_3%5E-%28aq.%29)
As, potassium and nitrate ions are present on both the sides of the reaction. Thus, it will not be present in the net ionic equation and are spectator ions.
The net ionic equation for the above reaction follows:
![Pb^{2+}(aq.)+SO_4^{2-}(aq.)\rightarrow PbSO_4(s)](https://tex.z-dn.net/?f=Pb%5E%7B2%2B%7D%28aq.%29%2BSO_4%5E%7B2-%7D%28aq.%29%5Crightarrow%20PbSO_4%28s%29)
Hence, the net ionic equation is written above.
Structures such as the ribosome, endoplasmic reticulum, and mitochondria cannot be viewed by the 10x objective lens. These organelles are too small to be viewed with low magnification and require over 2000x magnification. At low magnification structures such as the cell wall, vacuoles, and cytoplasm can be viewed.
Answer:
0.034 M
Explanation:
1/[A] = kt + 1/[A]o
[A] = ?
k= 0.04556
t= 10.0 minutes or 600 seconds
[A]o = 0.50 M
1/[A] = (0.04556 × 600) + 1/0.50
[A] = 0.034 M