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alexgriva [62]
3 years ago
11

A weather balloon contains 1.10X10 to the power of 5 mol of helium and has a volume of 2.70x10 to the power of 6 L at 1.00 atm p

ressure. Calculate the temperature of the helium
Chemistry
1 answer:
olchik [2.2K]3 years ago
4 0

Answer:

299.14 K or 26°C

Explanation:

The ideal gas law, also called the general gas equation, is the equation of state of a hypothetical ideal gas.

The ideal gas law is often written as

PV = nRT

where P ,V and T are the pressure, volume and absolute temperature;

n is the number of moles of gas and  R is the ideal gas constant.

n=1.10 x 10^5 mol  

V= 2.70 x 10^6 L  

P= 1.00 atm= 101.325 kPa  

R= 8.314 kPa*L/ mol*K

when the formula is  rearranged, T=PV/ nR  

T = (101.325kPa * 2.70 x 10^6 L)/ (1.10 x 10^5 mol * 8.314 kPa*L/ mol*K)  

T = 299.1421917 K

or

T = 299.14 - 273.15 = 25.99 =  26°C

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Answer:

Explanation has been given below.

Explanation:

  • Chloroform has three polar C-Cl bonds. Methylene chloride has two polar C-Cl bonds. So it is expected that chloroform should be more polar and posses higher dipole moment than methylene chloride.
  • Two factors are liable for the opposite trend observed in dipole moments of methylene chloride and chloroform.
  • First one is the number of hyperconjugative hydrogen atoms present in a molecule. Hyperconjugation occurs with vacant d-orbital of Cl atom. Hyperconjugation amplifies charge separation in a molecule resulting higher dipole moment.
  • Methylene chloride has two hyperconjugative hydrogen atoms and chloroform has one hyperconjugative hydrogen atom.Therefore methylene chloride should have higher charge separation as compared to chloroform.
  • Second one is induction of opposite polarity in a C-Cl bond by another C-Cl bond in a molecule. Higher the opposite induction of polarity, lower the charge separation in a molecule and hence lower the dipole moment of a molecule.
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