The answer is wind forces and Earth’s rotation
Answer:
a) - 72.5°c
b) pressure = 3625.13 Pa
c) density = 0.063 kg/m^3
d) it is a subsonic aircraft
Explanation:
a) Determine Temperature
Temperature at 19.5 km ( 19500 m )
T = -131 + ( 0.003 * altitude in meters )
= -131 + ( 0.003 * 19500 ) = - 72.5°c
b) Determine pressure and density at 19.5 km altitude
Given :
Po (atmospheric pressure at sea level ) = 101kpa
R ( gas constant of air ) = 0.287 KJ/Kgk
T = -72.5°c ≈ 200.5 k
pressure = 3625.13 Pa
hence density = 0.063 kg/m^3
attached below is the remaining part of the solution
C) determine if the aircraft is subsonic or super sonic
Velocity ( v ) = 
= 
= 283.8 m/s
hence it is a subsonic aircraft
Answer:
Option A.
A fan is turned from high speed to low speed.
Explanation:
It is important to note that air is also a fluid.
In a system, static pressure of air increases with the speed of rotation of the fan. This is because when the speed of the fan is increased, the force with which it is pushing the air molecules is increased. Since pressure is a relationship between force and area, the pressure of the air molecules will be increased.
Conversely, when the speed of the fan is reduced, the priming force on the air molecules will be reduced, hence the pressure of the air will drop.
This makes option A the correct option
Answer:
velocity changes over time.
Answer:
Option A. 1 bar = 1 atm
Explanation:
Pressure has various units of measurement. Each unit of measurement can be converted to other units of measurement. For example:
1 atm = 1 bar
1 atm = 760 mmHg
1 atm = 760 torr
1 atm = 1×10⁵ N/m²
1 atm = 1×10⁵ Pa
With the above conversion scale we can convert from one unit to the other.
Considering the question given above, it is evident from the coversion scale illustrated above that only option A is correct.
Thus,
1 bar = 1 atm
