Answer:
2.74
Explanation:
Magnification = image distance/object distance
Mag = v/u
Given
v = 46cm
u = 16.8
Magnification = 46/16.8
Magnification = 2.74
Hence the magnification is 2.74
Answer:
Net displacement = 0
Distance traveled = 2PQ <_up and down
Explanation:
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<span>torque = rF
= 0.1(10)
=1 Nm</span>
To reach a vertical height of 13.8 ft against gravity, which has an acceleration of 32 ft/s^2, the required vertical speed can be calculated from the equation:
vi^2 - vf^2 = 2*g*h
Given that it has vf = 0 (it is not moving vertically at its maximum height), g = 32, and h = 13.8, we can solve for vi:
vi^2 = 29.72 ft/s
This is only its vertical speed, so this is equivalent to its original speed multiplied by the sine of the angle:
29.72 ft/s = (v_original)*(sin 42.2<span>°</span>)
v_original = 44.24 ft/s
Converting to m/s, this can be divided by 3.28 to get 13.49 m/s.
Yes it can, because −3.5 lies to the left of −0.5.
Yes it can, because −3.5 lies to the right of −0.5.
No it cannot, because −3.5 lies to the left of −0.5.
No it cannot, because −3.5 lies to the right of −0.5.
Yes it can, because −3.5 lies to the left of −0.5.
Answer: Option A.
<u>Explanation:</u>
This option has been chosen because the left of the 0 has been shaded and all the negative values lies on the left of zero. So -3.5 lies to the left of -0.5 and is in the shaded region of the number line.
In a number line, the figure -3.5 lies on the left side compared to the number -0.5 because the higher the value on the negative side of the number line, more left it would be on the number line.
